Solid like a ice cube
Liquid like water
Gas=water vapor orHelium
Explanation:
Q1. Given:
v = 0 m/s
a = -5.5 m/s²
t = 3.5 s
Find: Δx
Δx = vt − ½ at²
Δx = (0 m/s) (3.5 s) − ½ (-5.5 m/s²) (3.5 s)²
Δx ≈ 33.7 m
Q2. Given:
Δx = 400 m
v₀ = 7.0 m/s
v = 35 m/s
Find: a
v² = v₀² + 2aΔx
(35 m/s)² = (7.0 m/s)² + 2a (400 m)
a = 1.47 m/s²
Answer:
4 m/s
Explanation:
It doesn't state it clearly in the problem, but I assume that the shores of the river are parallel and the man reaches the other side perpendicular from where he started (see attached image).
There are an infinite number of ways the swimmer can go from point A to point B, but the shortest time is of course a straight line. We know that the net speed along this line is 3 m/s. We also know the swimmer's speed is 5 m/s. Since the net velocity vector is perpendicular to the river's velocity, we can use Pythagorean theorem.
vᵣ² + (3 m/s)² = (5 m/s)²
vᵣ = 4 m/s
The water in the river flows at a speed of 4 m/s.
Answer:
A
Explanation:
Laddering can also be used as an overall retirement planning approach for all retirement investments. The idea is to separate CDs, cash, bonds, annuities, and others into different "ladders" (or "buckets" or "baskets") depending on when the asset is expected to be liquidated to fund the retirement revenue stream.
Explanation:
A projectile motion may be defined as that form of a motion that is experienced by an object or a particle which is projected near the surface of the Earth and the particle moves along the curved path subjected to gravity force only.
Thus a projectile motion is always acted upon by a constant acceleration due to gravity in the down ward direction.
In the context, Quinn shoots two particle x and y from his sling shot and he observes that both his projectiles travels in a parabola curve in the air. Both the object x and y touches the ground a distance apart from him which is known as the range and it depends upon the velocity of the projectile. Both the projectile reaches a maximum height and then drop on the ground in a parabola shape.