75/135 and 18/135
just times 9 and 15, 9 and 2, and then 15 and 5
yep answers is 7 my little buddy
Answer:
The dilation scale factor is
.
Step-by-step explanation:
The image is the dilated form of its preimage if and only if the following conditions are observed:
1) ![K' = \alpha_{1} \cdot K](https://tex.z-dn.net/?f=K%27%20%3D%20%5Calpha_%7B1%7D%20%5Ccdot%20K)
2) ![T' = \alpha_{2} \cdot T](https://tex.z-dn.net/?f=T%27%20%3D%20%5Calpha_%7B2%7D%20%5Ccdot%20T)
3) ![P' = \alpha_{3} \cdot P](https://tex.z-dn.net/?f=P%27%20%3D%20%5Calpha_%7B3%7D%20%5Ccdot%20P)
4) ![J' = \alpha_{4} \cdot J](https://tex.z-dn.net/?f=J%27%20%3D%20%5Calpha_%7B4%7D%20%5Ccdot%20J)
5) ![\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}](https://tex.z-dn.net/?f=%5Calpha_%7B1%7D%20%3D%20%5Calpha_%7B2%7D%20%3D%20%5Calpha_%7B3%7D%20%3D%20%5Calpha_%7B4%7D)
If we know that
,
,
,
,
,
,
and
, then the coefficients are, respectively:
,
,
, ![\alpha_{4} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Calpha_%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
As
, we conclude that the dilation scale factor applied in the preimage is equal to
.
7/10 you just get the decimal form of the numbers and find a simple decimal between them, which was 7, and put it over 10 so you get 7/10
Answer:
111111 aka i dont know
Step-by-step explanation: