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creativ13 [48]
3 years ago
15

Select the keyword or phrase that will best complete each sentence. A Claisen reaction is a nucleophilic ____________ in which a

n enolate is the nucleophile.
Chemistry
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

Substitution.

Explanation:

Claisen reaction was first published in 1887 by a prominent German chemist known as Rainer Ludwig Claisen.

A Claisen reaction is a nucleophilic substitution in which an enolate is the nucleophile. It's typically a reaction of two molecules of an ester to form a β-keto ester, in the presence of an alkoxide base. Thus, a Claisen reaction is simply a characteristic condensation reaction of esters through a nucleophilic carbonyl substitution with an enolate such as a ketone enolate or an ester enolate.

Furthermore, a Claisen reaction results in the formation of a carbon-carbon bond in the presence of a strong base to yield a β-keto ester.

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Match each substance with the correct designation for the equation HSO3- + CH3NH2 <=> SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C
Zanzabum

Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

SO_3^{2-} : conjugate base of HSO_3^-

CH_3NH_3^+ : conjugate acid of CH_3NH_2

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

4 0
3 years ago
A solution is made by dissolving 100. g of cobalt(III)chloride in 250. g of water. to make a solution that has a density of 1.25
Mariulka [41]

Answer:

Option A) (I) 2.42 m (II) 2.16 M

Explanation:

Let's determine some information.

Solute = CoCl₃ (molar mass = 165.29 g/m); mass of 100 g

Solvent = Water, mass of 250 g

Solution mass = mass of CoCl₃ + mass of water

250 g + 100 g = 350 g of solution

If we want to reach molarity (mol/L), let's determine solution volume with density:

Solution density = solution mass / solution volume

1.25 g/mL = 350 g / solution volume

Solution volume = 350 g / 1.25 g/mL = 280 mL

Let's convert the volume to L → 280 mL = 0.280L

Let's convert the mass of solute to moles = 100 g / 165.29 g/m →0.605 mol

Mol/L = 0.605 moles / 0.280 L = 2.16 M

Now let's calculate molalilty (mol/kg of solvet)

We must convert solvent mass to kg → 250g = 0.250 kg

Then, 0.605 moles / 0.250 kg =2.42 m

8 0
4 years ago
Lavoisier's discovery that air was not a substance but rather a mixture of nitrogen and oxygen is described as history-making. w
Taya2010 [7]
Antoine Lavoisier was part of a wealthy family in Paris. He pursued to study science upon realizing that chemistry or the study of the elements was not a well-studied field. His discovery of that air was a mixture of nitrogen and oxygen gave rise to the concept of COMBUSTION after repeating the experiments made by Priestly using mercury and other metal oxides. 

The event was such a history-making because it disproved that concept that air was a pure substance along with 3 others: earth, fire, and water. 
6 0
3 years ago
I need help FAST ASAP
kiruha [24]
In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.

1.  Na⁺     ,    Cl⁻    , NaCl   ---> sodium chloride (this is most commonly known as table salt)

2. C⁴⁺       , O²⁻     , CO₂  ---> carbon dioxide

3. Al³+     , Cl⁻       , AlCl₃   ----> aluminum chloride

4. Ca²⁺     , Cl⁻     , CaCl₂    ---> calcium chloride

5. Li⁺        , Br⁻      , LiBr       ---> lithium bromide

6. Mg³⁺     , O²⁻      , Mg₂O₃   ----> magnesium oxide

7. K⁺        , I⁻          , KI   ---> potassium iodide

8. H⁺        , Cl⁻        , HCl  --> hydrogen chloride

9. H⁺        , Br⁻         , HBr ----> hydrogen bromide

10. Na⁺    , Br⁻         , NaBr   ---> sodium bromide
6 0
4 years ago
List two products derived from ethylene
laiz [17]
Ethylene is the starting material for the preparation of a number of two-carbon compounds including ethanol (industrial alcohol), ethylene oxide (converted to ethylene glycol for antifreeze and polyester fibres and films), acetaldehyde (converted to acetic acid), and vinyl chloride (converted to polyvinyl chloride).
8 0
2 years ago
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