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mamaluj [8]
3 years ago
10

What determines the ending units of a stoichiometry problem?

Chemistry
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

1.Write the balanced chemical equation.

2.Convert the units of the given substance (A) to moles.

3.Use the mole ratio to calculate the moles of wanted substance (B).

4.Convert moles of the wanted substance to the desired units.

Explanation:

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The first-order reaction, so2cl2 → so2 + cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 k. what percentage of the init
Svetradugi [14.3K]
For the 1st order reactions,rate constant (k) is mathematically expressed as

k = \frac{2.303}{t}log \frac{Co}{Ct}
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'

Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s

Therefore, we have
</span>2.20 × 10^-5 = \frac{2.303}{7200}log \frac{100}{Ct}
∴ log\frac{100}{Ct} = 0.06877
∴, \frac{100}{Ct} = 1.1716
∴, Ct = 85.35%

Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
4 0
3 years ago
PLEASE HELP!
Tanzania [10]
Molar mass:

KCl = 74.55 g/mol

KClO3 = 122. 55 g/mol

  <span>Calculation of the mass of KClO3 :</span>

<span>2 KClO3 =  2 KCl + 3 O2</span>

2* 122.55 g KClO3 ------------------ 2 * 74.55 g KCl
mass KClO3 ?? --------------------- 25.6 g KCl

mass KClO3 = 25.6 * 2 * 122.55 / 2 * 74.55

mass KClO3 = 6274.56 / 149.1

mass = 42.082 g of  KClO3

Therefore:

1 mole KClO3 ---------------------- 122.55 g
?? moles KClO3 ------------------- 42.082 g

moles KClO3 = 42.082 * 1 / 122.55

moles KClO3 = 42.082 / 122.55

=> 0.343 moles of KClO3


Answer C

hope this helps!

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Answer:

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Explanation:

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