For the 1st order reactions,rate constant (k) is mathematically expressed as
k =

where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'
Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s
Therefore, we have
</span>2.20 × 10^-5 =

∴

= 0.06877
∴,

= 1.1716
∴, Ct = 85.35%
Thus, <span>
85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
Molar mass:
KCl = 74.55 g/mol
KClO3 = 122. 55 g/mol
<span>Calculation of the mass of KClO3 :</span>
<span>2 KClO3 = 2 KCl + 3 O2</span>
2* 122.55 g KClO3 ------------------ 2 * 74.55 g KCl
mass KClO3 ?? --------------------- 25.6 g KCl
mass KClO3 = 25.6 * 2 * 122.55 / 2 * 74.55
mass KClO3 = 6274.56 / 149.1
mass = 42.082 g of KClO3
Therefore:
1 mole KClO3 ---------------------- 122.55 g
?? moles KClO3 ------------------- 42.082 g
moles KClO3 = 42.082 * 1 / 122.55
moles KClO3 = 42.082 / 122.55
=> 0.343 moles of KClO3
Answer C
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Answer:
Cytoplasm.
Explanation:
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Answer:
kilograms
Explanation:
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