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mamaluj [8]
3 years ago
10

What determines the ending units of a stoichiometry problem?

Chemistry
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

1.Write the balanced chemical equation.

2.Convert the units of the given substance (A) to moles.

3.Use the mole ratio to calculate the moles of wanted substance (B).

4.Convert moles of the wanted substance to the desired units.

Explanation:

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Which of the following statements is true?
Liula [17]
D) during chemical reactions the number and types of atoms
4 0
3 years ago
Read 2 more answers
A sound wave traveling through a certain freshwater lake has a frequency of 349.2 Hz and a wavelength of 4.25 m. What is the spe
dmitriy555 [2]

Answer:

The speed of a spound wave in this water is 1484.1 m/s

Explanation:

Step 1: Data given

Frequency = 349.2 Hz

Wavelength = 4.25 m

Step 2: Calculate the speed

v = f*λ

⇒ with v= the speed of a sound wave in this water

⇒ with f = the frequency = 349.2 Hz

⇒ with λ = the wavelength = 4.25 m

v = 349.2 Hz * 4.25 m = 1484.1 m/s

The speed of a spound wave in this water is 1484.1 m/s

7 0
3 years ago
Read 2 more answers
A radioactive isotope, 14C decays to become 14N. After a time period of about 6,000 years, only about 12.5% of an original sampl
satela [25.4K]

Answer:

2000 years

Explanation:

A radioactive molecule will continuously decay and turn into another molecule. This nature of the radioactive molecule makes them can be used to estimate the age of an object. Half-life is the unit of time needed for radioactive molecules to decay to half of its mass. The formula for the mass remaining will be:

N(t)= N_{0} (\frac{1}{2})^{\frac{t}{t_{1/2} } }

Where

N(t)= number of the molecule remains

N0= number of molecule initially

t= time elapsed

t1/2= half time

We have all variable besides the half time, the calculation will be:

N(t)= N_{0} (\frac{1}{2})^{\frac{t}{t_{1/2} } }

0.125= 1 (\frac{1}{2})^{\frac{6000}{t_{1/2} } }

(\frac{1}{8})= (\frac{1}{2})^{\frac{6000}{t_{1/2} } }

(\frac{1}{2})^3= (\frac{1}{2})^{\frac{6000}{t_{1/2} } }

3= 6000/ (t1/2)

t1/2= 6000/3= 2000

The half-life is 2000 years

8 0
4 years ago
Please help me! This is due today.
natta225 [31]

Answer:

Steps of a scientific investigation include:

1. Identifying a research question or problem

2. Forming a hypothesis

3. Gathering evidence

4. Analyzing evidence

5. Deciding whether the evidence supports the hypothesis

6. Drawing conclusions

7. Communicating the results.

7 0
4 years ago
If 5.4 moles of Fe react with 4.7 moles of O2, what is the maximum amount of Fe2O3 (in moles) that can be produced? What is the
DIA [1.3K]

Answer:

2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Fe: 4 moles
  • O₂: 3 moles
  • Fe₂O3: 2 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?

moles of Fe =\frac{4. moles of Fe*4.7 moles of O_{2}}{3 moles of O_{2} }

moles of O₂= 6.27

But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.

So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?

moles of Fe_{2}O_{3}=\frac{5.4 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}

moles of Fe₂O₃= 2.7 moles

Then:

<u><em>2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.</em></u>

4 0
3 years ago
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