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olga nikolaevna [1]
3 years ago
7

The materials that are changed in a chemical reaction are called A. reactants B. coefficients C. products D. none of the above

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
6 0
Hello i got you the answer is A) reactants
Dmitry_Shevchenko [17]3 years ago
5 0
The materials that are changed in a chemical reaction are called A. reactants
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Physics<br><br><br><br><br><br><br> is my answer correct?
Digiron [165]

Explanation:

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If an object exerts a pressure of 16lb/in^2 and it has an area of 2 in^2 squared what is the weight of the object?
lesantik [10]

Answer:32Ib

Explanation:

Pressure=16Ib/in^2

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weight=pressure x area

Weight=16 x 2

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Take left to be the negative direction, and right to be positive. That means the forces on the squirrel would be -2N and 3N.

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This is the science of extremely small structures and is leading to advanced materials, devices and applications in energy, medi
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4 years ago
Irina finds an unlabeled box of fine needles, and wants to determine how thick they are. A standard ruler will not do the job, a
Vsevolod [243]

Answer:

d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m

Explanation:

The expression which represent the first diffraction minima by a circular aperture is given by d sin\Theta =1.22\lambda--------eqn 1

The angle through which the first minima is diffracted is given by tan\Theta =\frac{y_1}{D}---------eqn 2

As \Theta is very small so we can write sin\Theta =tan\Theta

So from eqn 1 and eqn 2 we can write

y_1=\frac{1.22\lambda D}{d}--------eqn 3

Here y_1 is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture

It is given that diameter of circular aperture is 14.7 cm so y_1=\frac{14.7}{2}=7.35 \ cm

Now putting all these value in eqn 3

d=\frac{1.22\lambda D}{y_1}

d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m

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