Answer:
1.93 x 10∧3 N
Explanation:
The picture attached shows the calculation
Answer:
The answer is a for Plato users.
Explanation:
Since the angle of the refracted ray moves away from the normal, it must be traveling in a faster medium.
Answer:
Torque,
Explanation:
Given that,
The loop is positioned at an angle of 30 degrees.
Current in the loop, I = 0.5 A
The magnitude of the magnetic field is 0.300 T, B = 0.3 T
We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

Let us assume that, 
is the angle between normal and the magnetic field, 
Torque is given by :

So, the net torque about the vertical axis is
. Hence, this is the required solution.
Answer:
do you mean stages or branches
Answer:Shifted towards Left by distance of 2.243 m
Explanation:
Given
Mass of john 
Mass of barbara 
John is standing at 
Barbara is standing at 




Now if they change their Position then



Thus we can see that center of mass shifted towards left by a distance of
because heavier is shifted towards left