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Answer:
Can you zoo m into the photo a little?
Explanation:
Answer:
24.5 m/s
Explanation:
Since the work done by the electric field on the charge equals the kinetic energy of the ball, then
qV = 1/2mv²
and v = √(2qV/m)
where q = charge = + 0.05 C, V = potential difference = 12.0 V, m = mass of ball = 2.0 g = 0.002 kg
Substituting the values into v, we have
v = √(2 × + 0.05 C × 12.0 V/0.002 kg)
= √(1.2 CV/.002 kg)
= √(600 CV/kg)
= 24.5 m/s
Answer:
Explanation:
Here we want to find the external resistance of the circuit.
First of all, the terminal voltage of a battery is given by:
where
is the emf
I is the current
r is the internal resistance
According to Ohm's law, when the battery is connected to the external resistance, the voltage on the battery is equal to the voltage drop on the resistor, which is:
where
R is the resistance of the external resistor
Combining the two equations,
Here we have:
is the emf of this battery
is the internal resistance
I = 2 A is the current in the circuit
Solving for R, we find: