Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
Answer:
<u>Given</u>: base = 10.4ft, height = 12.5
Area of octagon = 8(1/2 × b × h)
- 8(1/2 × 10.4 × 12.5)
- 520ft²
Volume of pool = 520ft² × 3ft
Now, 1 cubic ft takes 7.5 gallons to fill.
Therefore, 1560 cubic ft takes,
So, <u>Correct choice</u> - [D] 11,700.
5x + 4y = 32 ⇒ 45x + 36y = 288
9x - 1y = 33 ⇒ <u>45x - 5y = 165</u>
<u>41y</u> = <u>123</u>
41 41
y = 3
5x + 4(3) = 32
5x + 12 = 32
<u> - 12 - 12</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
(x, y) = (4, 3)
Answer:
right
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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