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tatiyna
2 years ago
5

Engineering problems and it solutions it machine design​

Engineering
1 answer:
jasenka [17]2 years ago
4 0

Answer:

Roads, bridges everything

Explanation:

Engineering is one of the fields that fathoms the most impact of our problems in the world. As engineers, our goal is to change the world with inventions and solutions that influence everyone’s lives. We get to dream and plan all the most interesting mechanisms,..

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Does somebody know how to do this?
maksim [4K]
No I don’t sorry, I hope you do well
4 0
2 years ago
53. The plan of a building is in the form of a rectangle with
schepotkina [342]

Answer: 150m

Explanation:

The following can be depicted from the question:

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Therefore, the plinth area of the building will be:

= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

= 10 × 15

= 150m

7 0
3 years ago
When would working with machinery be a common type of caught-in and caught-between<br> hazard?
tigry1 [53]

Answer:

A working with machinery be a common type of caught-in and caught-between  hazard is described below in complete detail.

Explanation:

“Caught in-between” accidents kill mechanics in a variety of techniques. These incorporate cave-ins and other hazards of tunneling activity; body parts extracted into unconscious machinery; reaching within the swing range of cranes and other installation material; caught between machine & fixed objects.

6 0
2 years ago
Water vapor at 5 bar, 320°C enters a turbine operating at steady state with a volumetric flow rate of 0.65 m3/s and expands adia
harina [27]

Answer:

Power = 371.28 kW

Explanation:

Initial pressure, P1 = 5 bar

Final pressure, P2 = 1 bar

Initial temperature, T1 = 320°C

Final temperature, T2 = 160°C

Volume flow rate, V = 0.65m³/s

From steam tables at state 1,

h1 = 3105.6 kJ/kg, s1 = 7.5308 kJ/kgK

v1 = 0.5416 m³/kg

Mass flow rate, m = V/v1

m = 1.2 kg/s

From steam tables, at state 2

h2 = 2796.2 kJ/kg, s2 = 7.6597 kJ/kgK

Power developed, P = m(h1 - h2)

P = 1.2(3105.6-2796.2)

P = 371.28 kW

8 0
3 years ago
A 4140 steel shaft, heat-treated to a minimum yield strength of 100 ksi, has a diameter of 1 7/16 in. The shaft rotates at 600 r
velikii [3]
Answer:










Explanation:



4140-40 I’d pick wood




I hope this helps! :)
4 0
2 years ago
Read 2 more answers
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