Answer:
![97.085\ \text{kPa}](https://tex.z-dn.net/?f=97.085%5C%20%5Ctext%7BkPa%7D)
Explanation:
= Gauge pressure = 2.2 atm = ![2.2\times 101325=222915\ \text{Pa}](https://tex.z-dn.net/?f=2.2%5Ctimes%20101325%3D222915%5C%20%5Ctext%7BPa%7D)
= Absolute pressure = ![3.2\ \text{bar}=3.2\times 10^5\ \text{Pa}](https://tex.z-dn.net/?f=3.2%5C%20%5Ctext%7Bbar%7D%3D3.2%5Ctimes%2010%5E5%5C%20%5Ctext%7BPa%7D)
= Local atmospheric pressure
Absolute pressure is given by
![P_{abs}=P_{atm}+P_g\\\Rightarrow P_{atm}=P_{abs}-P_g\\\Rightarrow P_{atm}=3.2\times 10^5-222915\\\Rightarrow P_{atm}=97085\ \text{Pa}=97.085\ \text{kPa}](https://tex.z-dn.net/?f=P_%7Babs%7D%3DP_%7Batm%7D%2BP_g%5C%5C%5CRightarrow%20P_%7Batm%7D%3DP_%7Babs%7D-P_g%5C%5C%5CRightarrow%20P_%7Batm%7D%3D3.2%5Ctimes%2010%5E5-222915%5C%5C%5CRightarrow%20P_%7Batm%7D%3D97085%5C%20%5Ctext%7BPa%7D%3D97.085%5C%20%5Ctext%7BkPa%7D)
The local atmospheric pressure is
.
Answer:
darts,” a smart, creative and highly-enjoyable drama about a team of intelligent, hard-working and ambitious high school students who enter a prestigious robotics competition, and their dedicated science teacher who mentors, educates, pushes and inspires them, is a rousing, uplifting, spirited–and excellent–film and a great start to the new film
Answer:
Read the passage. Then, answer the questions about the metaphor in boldface in the text.
Lately, I've been so overwhelmed with school and sports. There was a time when I enjoyed going to classes and going to practice every afternoon. Now, everything is piling up and wearing me down. Thankfully, I get to see you every day. You are truly the sunshine of my life. Thank you for making me laugh when I'm feeling down.
What is the context of the passage?
What is being compared in the metaphor?
What is the meaning of the metaphor?
Explanation:
Answer:
Explanation:
We know that Drag force![F_D](https://tex.z-dn.net/?f=F_D)
![F_D=\dfrac{1}{2}C_D\rho AV^2](https://tex.z-dn.net/?f=F_D%3D%5Cdfrac%7B1%7D%7B2%7DC_D%5Crho%20AV%5E2)
Where
is the drag force constant.
A is the projected area.
V is the velocity.
ρ is the density of fluid.
Form the above expression of drag force we can say that drag force depends on the area .So We should need to take care of correct are before finding drag force on body.
Example:
When we place our hand out of the window in a moving car ,we feel a force in the opposite direction and feel like some one trying to pull our hand .This pulling force is nothing but it is drag force.
Answer:
The right choice would be Option b (2.545).
Explanation:
The given values are:
The aggregate blend will be:
= 55%
= 2.631
= 25%
= 2.331
= 20%
= 2.609
Now,
On applying the formula, we get
⇒ ![G_{BA}=\frac{W_A+W_B+W_C}{\frac{W_A}{G_A} +\frac{W_B}{G_B} +\frac{W_C}{G_C}}](https://tex.z-dn.net/?f=G_%7BBA%7D%3D%5Cfrac%7BW_A%2BW_B%2BW_C%7D%7B%5Cfrac%7BW_A%7D%7BG_A%7D%20%2B%5Cfrac%7BW_B%7D%7BG_B%7D%20%2B%5Cfrac%7BW_C%7D%7BG_C%7D%7D)
On substituting the values, we get
⇒ ![=\frac{55+25+20}{\frac{55}{2.631} +\frac{25}{2.331} +\frac{20}{2.609}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B55%2B25%2B20%7D%7B%5Cfrac%7B55%7D%7B2.631%7D%20%2B%5Cfrac%7B25%7D%7B2.331%7D%20%2B%5Cfrac%7B20%7D%7B2.609%7D%7D)
⇒ ![= \frac{100}{\frac{55}{2.631} +\frac{25}{2.331} +\frac{20}{2.609}}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B100%7D%7B%5Cfrac%7B55%7D%7B2.631%7D%20%2B%5Cfrac%7B25%7D%7B2.331%7D%20%2B%5Cfrac%7B20%7D%7B2.609%7D%7D)
⇒ ![=2.545](https://tex.z-dn.net/?f=%3D2.545)