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Ymorist [56]
3 years ago
13

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Engineering
2 answers:
kakasveta [241]3 years ago
7 0

Answer:

With what?

Explanation:

Brainliest?

Jobisdone [24]3 years ago
3 0

Answer:

what do you need

Explanation:

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Find: factor of safety (n)for point A and B by using both MSS and DE (you can neglect shear stress due to shear force and also n
gladu [14]

Answer:

Hello your question is incomplete attached below is the complete question

Answer : Factor of safety for point A :

i) using MSS

(Fos)MSS =  3.22

ii) using DE

(Fos)DE = 3.27

Factor of safety for point B

i) using MSS

(Fos)MSS =  3.04

ii) using DE

(Fos)DE = 3.604

Explanation:

Factor of safety for point A :

i) using MSS

(Fos)MSS =  3.22

ii) using DE

(Fos)DE = 3.27

Factor of safety for point B

i) using MSS

(Fos)MSS =  3.04

ii) using DE

(Fos)DE = 3.604

Attached below is the detailed solution

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A crankcase heater is often used to prevent refrigerant from mixing with compressor oil during periods of:
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The acceleration of a particle is given by a = 2t − 10, where a is in meters per second squared and t is in seconds. Determine t
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Answer

given,

a = 2 t - 10

velocity function

we know,

\dfrac{dv}{dt}=a

\dfrac{dv}{dt}=(2t-10)

integrating both side

\int dv =\int (2t -10) dt

 v = t² - 10 t + C

at t = 0   v = 3

so, 3 = 0 - 0 + C

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Velocity function is equal to v = t² - 10 t + 3

Again we know,

\dfrac{dx}{dt}=v

\dfrac{dx}{dt}=(t^2-10t + 3)

integrating both side

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x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t + C

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