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pychu [463]
2 years ago
6

If the adoms dont work are they dead

Chemistry
1 answer:
Aleks [24]2 years ago
8 0

Answer:  no

Explanation:

Atoms are not and have never been alive so they can't be considered dead. they simply do not meet any reasonable of life, primarily because they are not complex.

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Global Precipitation Measurement (GPM) is a tool scientists use to forecast weather. Which statements describe GPM? Select three
Simora [160]

Answer:

It is a satellite that collects data about rain and snow.

• Its orbit covers 90 percent of Earth's surface.

• The sensors measure microwaves.

Explanation:

Correct on edge

4 0
3 years ago
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Which of the following is a direct result of global warming that is causing endangerment of polar bears?
frez [133]

increased warmth causing glaciers to melt

you're welcome! :)

3 0
2 years ago
HURRY I"M BEING TIMED!!!! if an unknown solution has a pH of 2. how would you classify this solution?
Sergeu [11.5K]
An acid, acids have a pH less than 7
7 0
3 years ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

8 0
3 years ago
Use the following balanced reaction to solve 1-3:
tino4ka555 [31]

Answer:

1.96g H2

Explanation:

P4 = 123.9g/mol

H2 = 2.02g/mol

\frac{20g P_{4} }{1} * \frac{1 mol P_{4} }{123.9g} * \frac{6 mol H_{2} }{1 mol P_{4} } * \frac{2.02g H_{2} }{1 mol H_{2} } = 1.96g H2

6 0
2 years ago
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