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-BARSIC- [3]
2 years ago
14

A 0.0100 mol sample of Ca(OH)2 requires 50.00 mL of aqueous HCl for neutralization according to the reaction below. What is the

concentration of the HCl? Equation: Ca(OH)2(s) + 2HCl(aq) → CaCl2(aq) + H2O(l)
Chemistry
1 answer:
harkovskaia [24]2 years ago
6 0

Answer:Cm=o,4 (Mol/l)

Explanation:

Ca(OH)2(s) + 2HCl(aq) → CaCl2(aq) + H2O(l)

0,01                 0,02

CM=n/V

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2 years ago
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600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c
Ludmilka [50]

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k=1.20x10^{-3} s^{-1}

Explanation:

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v=\frac{-d[A]}{[A]}=k[A]

Integranting both sides of the equation we get:

\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

ln\frac{[A]}{[A]_{0} } =-kt

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8 0
3 years ago
How many moles of HCl are present in 0.70 L of a 0.63 M HCl solution?
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So the molarity equation is moles of solute/liters of solution. so i’m pretty sure the answer should be 0.63/0.70= .9
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2 years ago
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