Question

Can someone help with these

Answer 1

One

Givens

• delta B = 0.20 T/s
• A = 0.07 m^2
• R = 3.5 ohms

Formula

Φ = ΔB*A

e = Φ

Solution (first part)

e = 0.2 * 0.07

e = 0.014 emf

Solution (second part)

i = e/R

i = 0.014 / 3.5

i = 4 * 10^-3

i = 4 ma

Answer

A

Two

Givens

N = 200 turns

Φ = 30 degrees

Delta B = 0.45 T/s

phi = 30 degrees

r = 0.06 meters

Formula

e = -N * delta B * A * Cos(phi)

Solution

e = -200 * 0.45 (pi r^2) * Cos(30)

e = - 200 * 0.45 * (3.14 * 0.06^2) * cos(30)

e = 0.881 emf

Answer

A