<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent.
vi = 0
vf = x
d = ?
d = vi + 1/2 a t^2
d = 0 + 1/2 (9.8) (1.8)^2
d = 15.9 m (counting sig figs)</span>
Answer:
1.53seconds
Explanation:
Using first equation of motion :
V=U + at
Where final velocity (V) =+8.3m/s
Initial velocity (U) =+4.4m/s
Acceleration (a) = 0.65m/s^2
time(s)=?
V=U + at
+8.3^2 = +4.4 + 0.65 * t
Making t the subject of the formula :
Therefore, t= ( +8.3 - 4.4)/0.65 = 1.53seconds
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Answer:
The centripetal acceleration of the stone is 5 m/s²
Explanation:
The length of the string to which the stone is attached, r = 1 m
The speed with which the string is rotated, v = 5 m/s
The centripetal acceleration, 
, is given as follows;
Therefore, the centripetal acceleration of the stone found as follows;
The centripetal acceleration of the stone, = 5 m/s².
