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2 years ago

6

HELP PLZ 50 POINTS SPACE QUESTION

1 answer:

Naddik [55]2 years ago

5 0

During the winter, the Northern Hemisphere tilted away from the sun, receiving solar radiation at more of an angle. <u>This results in colder temperatures and more extreme temperature changes.</u>

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When you "crack" a knuckle, you suddenly widen the knuckle cavity, allowing more volume for the synovial fluid inside it and cau

PolarNik [594]

Answer:If a wave y(x, t) = (6.0 mm) sin(kx + (600 rad/s)t + Φ) travels along a string, how much time does any given point on the string take to move between displacements y = +2.0 mm and y = -2.0 mm?

Explanation:

6 0

3 years ago

Explain why saucepans are much more common with plastic handles than metal handles.

horrorfan [7]

Because it’s cheaper and efficient

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3 years ago

Read 2 more answers

A car traveling on a straight road at 10 meters per second accelerates uniformly to a speed of 21 meters per second in 12 second

labwork [276]

21+10=31 because you can see that 21 and 10 are in metres while 12 is in seconds so 21+10=31 is the answer.

6 0

3 years ago

Y=1/2 at^2 solve for t

Aloiza [94]

Explanation:

y = ½ at²

Multiply both sides by 2:

2y = at²

Divide both sides by a:

t² = 2y/a

Take the square root of both sides:

t = √(2y/a)

6 0

3 years ago

Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wal

OverLord2011 [107]

Answer:

The phase difference is $\Delta \phi = 1.9995 rad$

Explanation:

From the question we are told that

The distance between the loudspeakers is $d = 2m$

The distance of the listener from the wall $D = 81.7 \ m$

The frequency of the loudspeakers is $f = 4450Hz$

The velocity of sound is $v_s = 343 m/s$

The path difference of the sound wave that is getting to the listener is mathematically represented as

$\Delta z =\sqrt{d^2 + D^2} -D$

Substituting values

$\Delta z =\sqrt{2^2 + 81.7^2 } -81.7$

$\Delta z =0.0245m$

The phase difference is mathematically represented as

$\Delta \phi$ = $\frac{2 \pi}{\lambda } * \Delta z$

Where $\lambda$ is the wavelength which is mathematically represented as

$\lambda = \frac{v_s }{f}$

substituting value

$\lambda = \frac{343 }{4450}$

$\lambda = 0.0770 m$

Substituting value into the equation for phase difference

$\Delta \phi$ = $\frac{2 * 3.142 * 0.0245}{0.0770}$

$\Delta \phi = 1.9995 rad$

8 0

3 years ago