We have: K.E. = 1/2 mv²
Here: m = 3 Kg
v = 6 m/s
Substitute their values,
K.E. = 1/2 * 3 * 6²
K.E. = 1/2 * 3 * 36
K.E. = 54 J
In short, Your Answer would be 54 Joules
Hope this helps!
Answer:
To calculate anything - speed, acceleration, all that - we need <em>data</em>. The more data we have, and the more accurate that data is, the more accurate our calculations will be. To collect that data, we need to <em>measure </em>it somehow. To measure anything, we need tools and a method. Speed is a measure of distance over time, so we'll need tools for measuring <em>time </em>and <em>distance</em>, and a method for measuring each.
Conveniently, the lamp posts in this problem are equally spaced, and we can treat that spacing as our measuring stick. To measure speed, we'll need to bring time in somehow too, and that's where the stopwatch comes in. A good method might go like this:
- Press start on the stopwatch right as you pass a lamp post
- Each time you pass another lamp post, press the lap button on the stopwatch
- Press stop after however many lamp posts you'd like, making sure to hit stop right as you pass the last lamp post
- Record your data
- Calculate the time intervals for passing each lamp post using the lap data
- Calculate the average of all those invervals and divide by 40 m - this will give you an approximate average speed
Of course, you'll never find an *exact* amount, but the more data points you have, the better your approximation will become.
Answer:
80×5×10=4000J
so therefore, work done on the body is 4000J
Storm weather likely happens in the town when the air masses meet because of difference of temperature and humidity of both air masses.
<h3>What weather happens when air masses meet?</h3>
When air masses move by wind, they carry different weather conditions from the weather conditions of other region. This difference in weather conditions can create a severe storm.
So we can conclude that Storm weather likely happens in the town when the air masses meet because of difference of temperature and humidity of both air masses.
Learn more about air here: brainly.com/question/636295
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