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denis-greek [22]
3 years ago
11

What is the final electron acceptor in cellular respiration?

Chemistry
1 answer:
Artemon [7]3 years ago
5 0
<span>The potential of NADH and FADH2 is converted to more ATPthrough an electron transport chain with oxygen as the "terminal electron acceptor". Most of the ATP produced by aerobic cellular respiration is made by oxidative phosphorylation.

Hope this helps. :)

</span>
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The development of nuclear power has provided electricity for less money, but at a cost. What may be considered a "cost" of nucl
Schach [20]
D. A disadvantage of nuclear power is that waste products are unsafe and hard to store. They must be stored for many hundreds of years before they becomes safe and easier to dispose of, and we currently don't have a good method of storing them in the meantime.


4 0
3 years ago
Read 2 more answers
Given 6 moles of CuCl2, how many moles of AlCl, were made? SHOW the math below​
Anastasy [175]

Answer:

6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

Explanation:

Given data:

Moles of CuCl₂ = 6 mole

Moles of AlCl₃ produced = ?

Solution:

3CuCl₂ + 2Al → 2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ with AlCl₃ .

            CuCl₂        :        AlCl₃

                3            :          2

                6           :         2/3 ×6 = 4 mol

So, 6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

6 0
3 years ago
Are alkali metals good or not good to use as utensils when eating?
nekit [7.7K]

Answer:

no

Explanation:

"Alkali metals are among the most reactive of all metals, which makes them suitable for specific and limited uses.

Alkali metals include lithium, sodium, potassium, rubidium, cesium and francium. These metals have large atomic radii and generally lose electrons during reactions. "

- Reference

8 0
3 years ago
What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?
adell [148]

Answer:

There is 2.52 L of O2 collected

Explanation:

Step 1: Data given:

Temperature = 22.0 °C

Pressure = 728 mmHg = 728 /760 = 0.958 atm

Mass of KClO3 = 8.15 grams

Molar mass of KClO3 = 122.55 g/mol

Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3= 8.15 grams / 122.55 g/mol

Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

Step 5: Calculate vlume of O2

p*V = n*R*T

V = (n*R*T)/p

⇒ with n = the number of moles O2 = 0.09975 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = 22.0 °C = 273 +22 = 295 Kelvin

⇒ with p = 0.958 atm

V = (0.09975 * 0.08206 * 295) / 0.958

V = 2.52 L

There is 2.52 L of O2 collected

7 0
3 years ago
PLEASE HELP PICTURE BELOW
seraphim [82]

Answer:

A.      

sorry if  it's wrong

Explanation:

8 0
3 years ago
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