Answer:
(i) 208 cm from the pivot
(ii) Move further from the pivot
Explanation:
(i) Sum of the moments about the pivot of the seesaw is zero.
∑τ = Iα
(50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0
1250 Nm + 600 N x = 0
x = -2.08 m
Kenny should sit 208 cm on the other side of the pivot.
(ii) To increase the torque, Kenny should move away from the pivot.
D=-5m
a(gravity)=-9.8m/s^2
vi= 0m/s
t=?
use equation d=vi*t+0.5a*t^2
because vi=0, you can cross out vi*t because anything multiplied by 0= 0
rearrange the equation to say t^2=d/0.5a
t^2= -5/-4.9
t^2=1.02
find the square root...
final answer: t=1s
I think the answer is c.<span>holding a tray in the cafeteria line</span>
Answer:
Given
mᴀ = mʙ = mᴄ = 62 kg
Fᴀ = 480N
Fʙ = 240 N
Fᴄ = 600 N
Asked
aᴀ, aʙ, aᴄ = ?
Solution
Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is
so, we can calculate the acceleration of road A, road B and road C.
• for road A
aᴀ = 7,7419 m/s²
aᴀ = 7,75 m/s²
• for road B
aʙ = 3,8709 m/s²
aʙ = 3,87 m/s²
• for road C
aᴄ = 9,6774 m/s²
aᴄ = 9,68 m/s²
Explanation:
East.
momentum = mass x velocity
the direction of the momentum is the same as that of velocity.
