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Brilliant_brown [7]
3 years ago
12

A student measures the mass of a sample of a metallic element, M. Then the student heats the sample in air, where it completely

reacts to form the compound MO. The student measures the mass of the compound that was formed. Which of the following questions can be answered from the results of the experiment?
Chemistry
1 answer:
mixas84 [53]3 years ago
5 0

Answer:What is the actual Molar mass of M?

Explanation:

The mass of the M is measured before, and after heating. Therefore, its easy to calculate the oxygen required to heat the M. Applying that to the reaction M+O₂⇒MO, will get you all the information about the Oxygen, and therefore you can calculate the Molar mass of M.

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If I initially have a gas at a pressure of 12 atm, volume of 23 liters, and temperature of 200 K, and then I raise the pressure
CaHeK987 [17]

Answer : The volume of gas will be 29.6 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 12 atm

P_2 = final pressure of gas = 14 atm

V_1 = initial volume of gas = 23 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 200K

T_2 = final temperature of gas = 300K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{12atm\times 23L}{200K}=\frac{14\times V_2}{300K}

V_2=29.6L

Therefore, the new volume of gas will be 29.6 L

5 0
3 years ago
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Which property determines an atom's ability to attract electrons shared in a chemical bond?
ASHA 777 [7]
It is electronegativity.
4 0
3 years ago
Calculate the energy, in joules, required to ionize a hydrogen atom when its electron is initially in the n =2 energy level. The
qaws [65]

Answer:

E_{ionization}=5.45\times 10^{-19}\ J

Explanation:

E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules

For transitions:

Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

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Thus,

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J

E_{ionization}=5.45\times 10^{-19}\ J

4 0
3 years ago
Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

Have a nice day!
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