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Brilliant_brown [7]
3 years ago
12

A student measures the mass of a sample of a metallic element, M. Then the student heats the sample in air, where it completely

reacts to form the compound MO. The student measures the mass of the compound that was formed. Which of the following questions can be answered from the results of the experiment?
Chemistry
1 answer:
mixas84 [53]3 years ago
5 0

Answer:What is the actual Molar mass of M?

Explanation:

The mass of the M is measured before, and after heating. Therefore, its easy to calculate the oxygen required to heat the M. Applying that to the reaction M+O₂⇒MO, will get you all the information about the Oxygen, and therefore you can calculate the Molar mass of M.

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For most atoms, a stable configuration of electrons is attained when the atom __________. hints hint 1. (click to open) for most
sveticcg [70]

Correct answer: has a completely filled outermost shell

Atoms of the element with complete outermost shells are stable. So, in order to attain stability the atom either loses electrons or gains electrons to completely fill the outermost shell. The stable electronic configuration for the s and p-block elements is exhibited by the noble gases or the group 8 elements. All the unstable atoms try to attain the electronic configuration of the nearest noble gas with completely filled outermost shell.

5 0
3 years ago
The Law of _____states that substances combine in predictable proportions and that excess reactants remain unchanged.
RideAnS [48]

Answer: definite proportions.


Explanation:


1) The definite proportions law states that compounds will always have the same kind of atoms (elements) in the same mass proportion (ratios).


2) For example, a molecule of water will alwys have the same mass ratio of hydrogen atoms to oxygen atoms. That is what permits to obtain the chemical formula of the water molecule as H₂O.


The mass of the two hydrogen atoms will be in a fixed ratio respect to the mass of the oxygen atoms.


Then, if you have one reactant in less proportion than the other, respect to the ratio stated by the chemical formula of water, the former will react completely (it is the limiting reactant) with the corresponding (proportional) mass of the later. Then there will be an excess of the later reactant which will not react (will remain unchanged).


The reactants can only react in the proportion defined by the chemical formulas of the final products.

4 0
3 years ago
Read 2 more answers
Which statement is correct regarding the reaction ?
larisa86 [58]

The true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.

<h3>What is true about the given reaction?</h3>

The given reaction shows a reaction between A and B to form CD

The reaction is a reversible reaction.

A reversible reaction is a reaction which can proceed in either of two ways where the reactants can react to form the product and also the products an break down to form the reactants.

In the reaction given, as the concentration of A and b decreases, the concentration of CD increases and vice versa.

At equilibrium, the rate of formation of CD is equal to the the rate of decomposition of CD.

Therefore, the true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.

In conclusion, a reaction at equilibrium has the forward and backward reactions occurring at the sane rate.

Learn more about equilibrium reaction at: brainly.com/question/18849238

#SPJ1

5 0
1 year ago
Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro
attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the <u>chemical reaction</u>:

NaN_3~->~Na~+~N_2

The next step is to <u>balance the reaction</u>:

2NaN_3~->~2Na~+~3N_2

We can continue with the <u>mol calculation</u> using the molar mass of

NaN_3 (65 g/mol), so:

3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3

Now, with the<u> molar ratio</u> between NaN_3  and N_2  we can <u>calculate the moles</u> of N_2  (2:3), so:

0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2

With the molar mass of N_2 we can <u>calculate the grams</u>:

0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2

I hope it helps!

5 0
3 years ago
How does the law of conservation of mass apply to this reaction C2H4+4O2--&gt;4H2O+2CO2 .Only the oxygen needs to be balanced B.
r-ruslan [8.4K]
C2H4+4O2-->4H2O+2CO2

the answer is C
6 0
3 years ago
Read 2 more answers
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