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nadya68 [22]
3 years ago
8

Please helpppp... thank u ❤️​

Physics
2 answers:
Nadusha1986 [10]3 years ago
6 0

Answer:

For Ryan:

at \: highest \: point : v = 0 \\ velocity = 0 \:  {ms}^{ - 1}

For the football kicked:

s = ut  -  \frac{1}{2} g {t}^{2}  \\ for \: range : s = 0 \\ u \sin( \theta)  =  \frac{gt}{2}  \\ t  =  \frac{2u \sin(\theta) }{g}  \\ range(x) = ut \\ x =  \frac{ {2u {}^{2}  \sin(\theta) }^{} }{g}  \\ \frac{50 \times 9.8}{ {2318.9}^{} }  =  \sin(\theta)  \\  \\but \: 0 = u \sin(25)  - 2 \times 9.8 \times 50 \\ u = 2318.9 \:  {ms}^{ - 1}  \\  \theta = 12.2 \degree

Maksim231197 [3]3 years ago
4 0

Answer:

the highest point for the first question is 0 meters per second

the answer for question 2 is 45 degrees

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