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Colt1911 [192]
3 years ago
9

What stress would shift the equilibrium position of the following system to the right?

Chemistry
2 answers:
MakcuM [25]3 years ago
6 0

Answer:

Decreasing the concentration of N_2O_3 => To the left

Heating the system => To the left

Adding a catalyst  => No change

Increasing the concentration of NO => To the left

Explanation:

We have to analyze each case:

<u>Decreasing the concentration of N2O3 </u>

<u />

The compound N_2O_3 is a reactive. When we remove the concentration of this compound the reaction has to go to the left in order to restore the initial equilibrium.

<u>Heating the system </u>

<u />

In this case, the heat (energy) can be considered as a product because it has a negative sign. Therefore, if we add energy the reaction will move to the opposite side. The reactive side

<u>Adding a catalyst </u>

<u></u>

The addition of a catalyst doesn't change the equilibrium of any reaction. The catalyst addition affects the velocity of the reaction but not the equilibrium.

<u>Increasing the concentration of NO</u>

<u />

The NO is a product therefore if we increase the concentration of NO will displace the reaction to the opposite side. To the reactants side

yanalaym [24]3 years ago
4 0

Answer:

Decreasing the concentration of N2O3

Explanation:

This is because the products on the right of the reaction occupy more space. One (1) mole of NO and another mole of NO2 will occupy more space than the one (1) mole of N2O3. Therefore decreasing the concentration of N2O3 will shift the reaction to the right because the products will have more space to occupy – hence favoring equilibrium.

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