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olasank [31]
2 years ago
7

Calculate the grams of nitrogen in 125 g of NH4NO3

Chemistry
1 answer:
Marta_Voda [28]2 years ago
5 0

Answer:

43.75 g of Nitrogen

Explanation:

We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:

Mole of NH₄NO₃ = 1 mole

Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)

= 14 + 4 + 14 + 48

= 80 g/mol

Mass of NH₄NO₃ =?

Mass = mole × molar mass

Mass of NH₄NO₃ = 1 × 80 = 80 g

Next, we shall determine the mass of N in 1 mole of NH₄NO₃.

Mass of N in NH₄NO₃ = 2N

= 2 × 14

= 28 g

Thus,

80 g of NH₄NO₃ contains 28 g of N.

Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:

80 g of NH₄NO₃ contains 28 g of N.

Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.

Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen

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How many molecules are in 79g of fe2o3
horrorfan [7]
Convert grams —> mols and then mols —> atoms

We know that there are 6.02 x 10^23 atoms/mol

And we know that there are about 160 grams of fe2o3 per mol

So (79g fe2o3)/(160 g/mol) = .49 mol fe2o3

Now we use avogadro’s number to do

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3 years ago
In this chemical reaction, how many grams of h2 will react completely with6.50 moles of CO
geniusboy [140]

52 g of hydrogen H₂

Explanation:

I will assume that the problem is talking about the hydrogenation of carbon dioxide CO₂ not carbon monoxide CO. It is harder to reduce carbon dioxide than carbon monoxide and if you manage to reduce carbon dioxide you can reduce the carbon monoxide as well.

This reaction it will take place in the presence of catalyst at a specific temperature and pressure.

CO₂ + 4 H₂ → CH₄ + 2 H₂O

Now taking into the account the chemical reaction we devise the following reasoning:

if         1 mole of CO₂ react with 4 moles of H₂

then   6.5 moles of CO₂ react with X moles of H₂

X = (6.5 × 4) / 1 = 26 moles of H₂

number of moles = mass / molecular wight

mass = number of moles × molecular wight

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Learn more about:

hydrogenation reaction

brainly.com/question/13592967

#learnwithBrainly

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