I do believe the answer would be 2.0 each fin because 2.0+2.0=4.0 do that twice you should get 8.0 let me know if that is correct please hope I helped
Answer:
Option E is correct.
There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.
Explanation:
Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as
R = (u² sin 2θ)/g
where
u = initial velocity of the projectile = 20 m/s
θ = angle above the horizontal at which the projectile was launched = 30°
g = acceleration due to gravity = 9.8 m/s²
R = (30² sin 60°) ÷ 9.8
R = 78.53 m
So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.
There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.
Hope this Helps!!!
Answer:
dimensions of k are kg / s^2
Explanation:
F=ma (Newton's second law)
F=-kx (Hooke's law)
so equate both
-kx = ma
k = -ma/x
= mass * acceleration / distance (dimensions, -1 has no dimension)
= kg * m/s^2 / m
= kg / s^2
Answer:
700 mL or 0.0007 m³
Explanation:
P₁ = Initial pressure = 2 atm
V₁ = Initial volume = 350 mL
P₂ = Final pressure = 1 atm
V₂ = Final volume
Here the temperature remains constant. So, Boyle's law can be applied here.
P₁V₁ = P₂V₂

So, volume of this sample of gas at standard atmospheric pressure would be 700 mL or 0.0007 m³
Answer:
8.3 x 10⁻⁷ C
Explanation:
Electric flux will enter the face at x=0 and exit at face x= 25 m
On the other faces , field lines are parallel so no flux will enter or exit .
Flux entering the face at x = 0
= electric field x face area
= 560 x 25 x 25 = 350000 weber
Flux exiting the face at x = 25
= 410 x 25 x25
= 256250 weber
Net flux exiting from cube ( closed face )
350000 - 256250 = 93750 web
Apply gauss'es theorem
Q / ε = Flux coming out
Q is charge inside the closed cube
Q / ε = 93750
Q = 8.85 x 10⁻¹² x 93750
= 8.3 x 10⁻⁷ C