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2 years ago

A man walked 50 m to the south, turned, walked 40 m to the west.

Physics

1 answer:

MaRussiya [10]2 years ago

3 0

Answer:

Direction is N 51.3° E

Explanation:

» From trigonometric ratios:

${ \tt{ \red{ \tan( \theta) = \frac{opposite \: { \blue{(south)}}}{adjacent \: { \blue{(west)}}} }}} \\ \\ { \tt{ \tan( \theta) = \frac{50}{40} = \frac{5}{4} }} \\ \\ { \tt{ \theta = { \tan }^{ - 1} ( \frac{5}{4}) }} \\ \\ { \tt{ \theta = 51.3 \degree}} \\ \\ { \boxed{ \tt{ \: direction : \:{ \green{N }}\: 51.3 \degree \: { \green{ E }}}}}$

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The headwater of three different river systems are also found in Wyoming. Identify these three river systems.

S_A_V [24]

Answer:

The Wind Missouri-Mississippi, The Snake Columbia, and the Green-Colorado drainage.

Explanation:

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3 years ago

A child moving at constant velocity carries a 2 N ice cream cone 1 m across a level surface. Is she doing work?

PSYCHO15rus [73]

Answer:

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Explanation:

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3 years ago

What is velocity change divided by time change?

Luda [366]

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4 years ago

To measure the coefficient of kinetic friction by sliding a block down an inclined plane the block must be in equilibrium.

lozanna [386]

Answer:

Explanation:

A block sliding down an inclined plane, is subject to two external forces along the slide.
One is the component of gravity (the weight) parallel to the incline.
If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:

$F_{gp} = m*g* sin \theta (1)$

(taking as positive the direction of the movement of the block)

The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:

$F_{f} = \mu_{k} * N (2)$

The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:

$N = m*g* cos \theta (3)$

In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:

$m*g* sin \theta = \mu_{k} * m*g* cos \theta$

As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:

$\mu_{k} = tg \theta$

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3 years ago

33] You have long hair, you should:

Sveta_85 [38]

Answer:

Explanation:

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3 years ago

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