The answer is: "10" .
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" A centimeter and millimeter differ from each other by a factor of "10" .
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Note:
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100 cm = 1 m
1000 mm = 1m
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100 * (10) = 1000 .
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The answer is: "10".
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" A centimeter and millimeter differ from each other by a factor of "10".
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4 carbon electrons. Hope this helps have a nice day
Answer:
2 L is the new volume
Explanation:
We can apply the Ideal Gases Law to solve the problem.
At STP, we kwow that 1 mol of gas occupy a volume of 22.4 L
Then, how many moles do we have in 1 L?
Let's do it by a rule of three:
(1L . 1 mol) / 22.4L = 0.0446 moles
These moles are at 1 atm and 273 K of temperature, so let's change our conditions.
P . V = n . R .T
1 atm . V = 0.0446 mol . 0.082 L.atm/mol K . 546 K
V = 2 L
If we pay attention, we can notice that, if we double temperature, we double the volume.
Answer:
Water - H2O
Ammonia - NH3
Sulfur dioxide - SO2
Hydrogen sulfide - H2S
Ethanol - C2H6O
Explanation:
Those are some atoms with polar covalent bonds. Hope this helps!!
The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.
<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>
The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.
The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.
In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.
Moles = mass/molar mass
molar mass of acetic acid = 62 g/mol
molar mass of water = 18 g/mol
moles of vinegar = 5/62 = 0.08
moles of water = 95/18 = 5.28
total moles = 5.36
Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36
Mole ratio of vinegar to water = 0.015 : 0.985
In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.
Learn more about mole ratio at: brainly.com/question/19099163
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