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Rina8888 [55]
2 years ago
8

A beaker contains 450 g of water (H2O). If 9.2 g of calcium fluoride (CaF2) is added, what is the molality concentration of the

solution?
Chemistry
1 answer:
lord [1]2 years ago
6 0
Molality = number of mole of solute in  1kg= 1000g solvent.

Solute is CaF2.
Molar mass (CaF2) = M(Ca) +2M(F) = 40.1 + 2*19.0 = 78.1 g/mol

9.2 g CaF2 * 1 mol CaF2/78.1 g CaF2 = 0.12 mol CaF2

Solvent is water 450 g.

0.12 mol CaCl2 -------450 g water
x mol CaCl2    --------- 1000 g water

x=0.12*1000/450 = 0.27 

Molality is 0.27 (mol CaF2 in 1 kg water).

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Answer:

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Explanation:

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4 0
3 years ago
Isotopes of carbon differ with the respect to the number of
hodyreva [135]

Answer:

Neutrons.

Explanation:

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Where; X is the symbol of the element.

A is the atomic mass or number of nucleons.

Z is the atomic number or number of protons.

<em>Therefore, the number of neutrons = A - Z</em>

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<em>2. Carbon-13: it has an atomic mass of 13 with 6 numbers of proton and 7 numbers of neutron. </em>

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8 0
3 years ago
What is true about a block of ice at -10 degrees celsius as you continue to apply heat...
Y_Kistochka [10]

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4 0
3 years ago
An unknown aqueous metal analysis yielded a detector response of 0.255. When 1.00 mL of a solution containing 100.0 ppm of the m
AVprozaik [17]

Answer:

1.022ppm is the unknown concentration of the metal

Explanation:

Based on Lambert-Beer law, the increasing in signal of a detector is directly proportional to its concentration.

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0.99X + 1ppm produce 0.502, thus, X is:

0.255 * (0.99X + 1 / 0.502) =

X = 0.503X + 0.508

0.497X = 0.508

X =

1.022ppm is the unknown concentration of the metal

3 0
2 years ago
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Nata [24]

Answer:

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6 0
2 years ago
Read 2 more answers
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