Answer:
2240.92365 m/s
Explanation:
= Mass of electron = 
= Speed of electron = 
= Neutrino has a momentum = 
M = total mass = 
In the x axis as the momentum is conserved
In the y axis
The resultant velocity is
The recoil speed of the nucleus is 2240.92365 m/s
The solution would be like
this for this specific problem:
<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g =
v^2/r </span>
<span>v^2 = 4.5
g * r </span>
<span>v = sqrt
( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124
m/s</span>
So the pilot will black out for this dive at 124
m/s. I am hoping that these answers have satisfied your query and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.
It's by number of protons
The Coulomb force between two charges is defined as: Fc=(k*Q₁*Q₂)/r² where k=9*10^9 N m² C⁻², Q₁ and Q₂ are charges and r is the distance between those charges.
In our case:
Q₁=2*10^-6 C
Q₂=4*10^-6 C
r=2 m
Now we simply plug in the numbers into the equation:
Fc={(9*10^9)*(2*10^-6)*(4*10^-6)}/2^2=0.018 N
The Coulombs force between the two positive charges is Fc=0.018 N and it is a repulsive force because both charges are positive.
