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Nata [24]
3 years ago
13

4. The Voyager 1 and 2 spacecraft are now out beyond the orbit of Pluto. They have run out of fuel long ago but are still moving

at a constant speed of 50,000 mph. According to Newton's laws of motion, the Voyagers will A) eventually slow down and come to a stop in the middle of interstellar space. B) continue to move in the same way forever, no matter what happens. C) continue to move in the same way until acted upon by a force. D) eventually slow down, turn around and come back to Earth.
Physics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

C

Explanation:

According to Newton's first law of motion, which states that a body will continue in its state of rest or uniform motion unless acted upon by an external force to change its state of rest or uniform motion. So, the Voyagers spacecraft will continue to move in the same way at the constant speed of 50,000 mph unless acted upon by a force.

Andrews [41]3 years ago
6 0

Answer:

Option C is correct

Continue to move in the same way until acted upon by a force.

Explanation:

The newton's 1st law of motion states that:

<em>"If an object is at rest then it will stay at rest or if an object is in motion then it remains in motion at the same speed as before unless acted upon by some unbalanced force"</em>

The Voyager 1 and 2 spacecraft are still moving at a constant speed of 50,000 mph and they will keep on moving at this rate unless some unbalanced force acts on them.

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Answer:

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6 0
3 years ago
A 100 mH inductor whose windings have a resistance of 6.0 Ω is connected across a 12 Vbattery having an internal resistance of 3
Alexus [3.1K]

Answer:

The store energy in the inductor is 0.088 J

Explanation:

Given that,

Inductor = 100 mH

Resistance = 6.0 Ω

Voltage = 12 V

Internal resistance = 3.0 Ω

We need to calculate the current

Using ohm's law

V = IR

I=\dfrac{V}{R+r}

Put the value into the formula

I=\dfrac{12}{6.0+3.0}

I=1.33\ A

We need to calculate the store energy in the inductor

U=\dfrac{1}{2}LI^2

U=\dfrac{1}{2}\times100\times10^{-3}\times(1.33)^2

U=0.088\ J

Hence, The store energy in the inductor is 0.088 J

7 0
2 years ago
The magnitude of Earth’s magnetic field is about 0.5 gauss near Earth’s surface. What’s the maximum possible magnetic force on a
vampirchik [111]

Answer:

F = 1.5 \times 10^{-16} N

this force is 1.68 \times 10^{13} times more than the gravitational force

Explanation:

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KE = 1 keV

KE = 1 \times 10^3 (1.6 \times 10^{-19}) J

KE = 1.6 \times 10^{-16} J

now the speed of electron is given as

KE = \frac{1}{2}mv^2

now we have

v = \sqrt{\frac{2 KE}{m}}

v = 1.87 \times 10^7 m/s

now the maximum force due to magnetic field is given as

F = qvB

F = (1.6\times 10^{-19})(1.87 \times 10^7)(0.5 \times 10^{-4})

F = 1.5 \times 10^{-16} N

Now if this force is compared by the gravitational force on the electron then it is

\frac{F}{F_g} = \frac{1.5 \times 10^{-16}}{9.1 \times 10^{-31} (9.8)}

\frac{F}{F_g} = 1.68 \times 10^{13}

so this force is 1.68 \times 10^{13} times more than the gravitational force

4 0
3 years ago
the pressure of a gas is 100.0kpa and its volume is 500.0ml if the volume increase to 1000.0ml what is the new pressure of the g
Ket [755]

50Kpa

Explanation:

P1V1 = P2V2

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P1= 100. P2= ?

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100 × 500 = P2 × 1000

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50000/1000 = P2

50 = P2

P2 = 50Kpa

4 0
3 years ago
A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte
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Answer:

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Explanation:

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