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3 years ago

Extra points & brainlest to anyone that can help me with both answers

Chemistry

1 answer:

ki77a [65]3 years ago

3 0

Answer:

1st blank: Organelles

2nd blank: Plant

3rd blank: chloroplasts

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Pure, a bottled-water manufacturer, is pulled up by regulatory authorities for traces of ammonia in its products. pure forms a t

gulaghasi [49]

The initial report of the team formed by PURE may contain findings similar to the processes used in the disinfection of the water. Usual cases of ammonia presence in water are due to chloramine disinfection process. Also, they should also look into the storage of their facility and the end user which may also have a window of contamination.

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3 years ago

How many moles of K+ and PO4^3- ions are present in 20.0 mL of a 0.015 M solution of potassium phosphate?

Romashka-Z-Leto [24]

Answer:

$n_{K^+}=0.0009molK^+$

Explanation:

Hello,

In this case, the first step is to compute the number of moles of potassium phosphate in 20.0 mL (0.020L) of the 0.015-M (mol/L) solution as shown below:

$n=0.020L*0.015\frac{mol}{L}=0.0003mol$

Thus, these moles correspond to potassium phosphate moles, which molecular formula is K₃PO₄, therefore, one mole of this compound contains three moles of potassium ions as it has three as its subscript in the formula. Thereby, the moles of potassium ions result in:

$n_{K^+}=0.0003molK_3PO_4*\frac{3molK^+}{1molK_3PO_4} \\\\n_{K^+}=0.0009molK^+$

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3 years ago

Plutonium-236 is an alpha emitter with a half-life of 2.86 years. If a

Jobisdone [24]

Answer:

Explanation:

because its half life is shorter than the subsequent ones

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3 years ago

The atomic radius of an element

Greeley [361]

Explanation:

increases. because the num of electrons increass

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3 years ago

What mass of Na2CO3 will be required to dissolve in 0.3 L of water to make a 0.5 M solution?

Reptile [31]

The mass of $Na_2CO_3$ that will be required to be dissolved in water would be 15.9 grams

<h3>Solution preparation</h3>

Recall that: molarity = mole/volume in L

In this case, the volume is 0.3 L and the molarity is 0.5 M.

Thus, mole = molarity x volume = 0.5 x 0.3 = 0.15 moles

Mass of 0.15 moles $Na_2CO_3$ = 0.15 x 106 = 15.9 grams

More on solution preparation can be found here: brainly.com/question/14667249

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2 years ago