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3 years ago

VAMDNVABNATNAMDTEMCYSPLDDNHNMQTYYque es bandaaa

Physics

2 answers:

Sliva [168]3 years ago

8 0

Im sorry but i dont understand

kvasek [131]3 years ago

3 0

De que hablas bandaaaaaa

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a certain projetor uses a concave mirror for projecting an object's image on a screen .it produces on image that is 4 times bigg

IrinaK [193]

Answer:

f = 1 m

Explanation:

The magnification of the lens is given by the formula:

$M = \frac{q}{p}$

where,

M = Magnification = 4

q = image distance = 5 m

p = object distance = ?

Therefore,

$4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m$

Now using thin lens formula:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\$

f = 1 m

6 0

3 years ago

Mechanical energy is the sum of energy and potential energy.

MAVERICK [17]

Answer:

True, the total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy. This sum is simply referred to as the total mechanical energy.

Explanation: Hope it helps you:))))

have a good day

7 0

2 years ago

TRUE OR FALSE Light can travel through materials that you cannot see through, like wood or aluminum foil.

Keith_Richards [23]

i think its uhh......tralse

8 0

3 years ago

An electron has a kinetic energy of 10.1 eV. The electron is incident upon a rectangular barrier of height 18.2 eV and width 1.0

podryga [215]

Answer:

factor that the electron's probability of tunneling through the barrier increase 2.02029

Explanation:

given data

kinetic energy = 10.1 eV

height = 18.2 eV

width = 1.00 nm

wavelength = 546 nm

solution

we know that probability of tunneling is express as

probability of tunneling = $e^{-2CL}$ .................1

here C is = $\frac{\sqrt{2m(U-E}}{h}$

here h is Planck's constant

c = $\frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-10.1) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}$

c = 2319130863.06

and proton have hf = $\frac{hc}{\lambda } = {1240}{546}$ = 2.27 ev

so electron K.E = 10.1 + 2.27

KE = 12.37 eV

so decay coefficient inside barrier is

c' = $\frac{\sqrt{2m(U-E}}{h}$

c' = $\frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-12.37) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}$

c' = 1967510340

the factor of incerease in transmisson probability is

probability = $e^{2L(c-c')}$

probability = $e^{2\times 1\times 10^{-9} \times (351620523.06)}$

factor probability = 2.02029

3 0

3 years ago

Two objects, one of mass 17 kg and the other of mass 31 kg approach each other with the lighter one having a speed of 23 m/s. De

Phantasy [73]

<h2>ANSWER:</h2>

CARRY ON LEARNING

CAN YOU BRAINLEST ME

8 0

2 years ago

VAMDNVABNATNAMDTEMCYSPLDDNHNMQTYYque es bandaaa​

VAMDNVABNATNAMDTEMCYSPLDDNHNMQTYYque es bandaaa