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sammy [17]
3 years ago
10

Expression for calories burned during workout

Engineering
1 answer:
VMariaS [17]3 years ago
8 0
Women: Calories -((Age x 0.074) - (Weight x 0.05741) + (Heart Rate x 0.4472) – 20.4022) Time / 4.184 Men: Calories = ((Age x 0.2017) + (Weight 0.09036) + (Heart Rate x 0.6309) - 55,0969) x Time / 4.184
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The technique of smoothing out joint compound on either side of a joint is known as which of the following
Black_prince [1.1K]

Answer:

a is the answer to your questions

3 0
3 years ago
Why did you choose agricultural and biosystem as a course? Help me guys
Mazyrski [523]

Answer:

To be able to develop as a human and give back to the community. To ensure that people have safe food and water to drink, clean fuel and energy sources, and in general a safe enviornment to live in.

Explanation:

7 0
3 years ago
a centrifugal pump delivers water at the rate of 50kg/is . the inlet and outlet pressure are 2 bar and 6.2 bar respectively. the
Monica [59]

Answer:

21.6 kw

Explanation:

Given data:

m = 50 kg/s

Inlet pressure (p1) = 2 bar

outlet pressure(p2) = 6.2 bar

suction ( h1 ) = -2.2 m

delivery ( h2 ) = 8.5 m

d1 = 200 mm = 0.2 m

d2 = 100 mm = 0.1 m

Vs of water = 0.001 m^3/kg

next we have to determine the Q value

Q = V*A

Q = 0.001 * 50 = 0.05 m^3/s

next we have to calculate the various V's

V1 = Q/A1 = \frac{0.05*4}{\pi *0.2^2}  = 1.59 m/s

V2 = Q/A2 = \frac{0.05*4}{\pi *0.1^2} = 6.37 m/s

Determine the capacity of the electric motor

attached below is the detailed solution

7 0
3 years ago
You are to assess the biomechanics of a male’s arm using his bicep to hold a 20 kg object in his hand. The upper arm is perpendi
cestrela7 [59]

Answer:

Explanation:

The detailed analysis, with free body diagram and step by step calculations with appropriate substitution is as shown in the attached files.

5 0
4 years ago
A simple non-ideal Rankine cycle with water as the working fluid operates between the pressure limits of 15 MPa in the boiler an
konstantin123 [22]

Answer:

The right solution is "28.45%".

Explanation:

The given values are:

P_4=50\ kPa

h_4=0.7(2304.7)+340.5

    =1953.83 \ KJ/Kg

and,

P_3=15 \ mPa

h_3=hg

    =2610.8 \ KJ/Kg

s_3=sg

    =5.3108 \ KJ/Kgh

At 45,

⇒ x_{45} = \frac{5.3108-1.0912}{6.5019}

          =0.66

At P_4=50 \ Kpa,

h_f=340.54

or,

V_f=0.001030 \ m^3/Kg

then,

⇒ h_2=340.54+0.001030(15\times 10^{3}-50)

        =355.94 \ kJ/kg

hence,

The isentropic efficiency of turbine will be:

⇒ n_T=\frac{h_3-h_4}{h_3-h_{45}}

         =\frac{2610.8-1953.83}{2610.8-1836.26}

         =84.818 (%)

The thermal efficiency of cycle will be:

⇒ n_C=\frac{W_T-W_P}{2_{in}}

         =\frac{(2610.8-1953-83)-(355.93-340.54)}{2610.8-355.93}

         =28.45 (%)  

4 0
3 years ago
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