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lora16 [44]
3 years ago
5

A hydrauliic jack is rated at 5000 pound capacity. The area of the large piston on the jack is 4.45 Square inches. Calculate the

fluid pressure in the jack at maximum load . Calculate in units of psi (pounds/square inch)
Engineering
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

1123.6 pounds/ square inch.

Explanation:

Fluid pressure is the ratio of force or weight applied by the fluid per unit area.

i.e Fluid pressure = \frac{weight}{area}

The maximum load of the jack is obtained at its maximum capacity = 5000 pounds

Area of the large piston on the jack = 4.45 square inches

Thus,

Fluid pressure = \frac{5000}{4.45}

                        = 1123.5955

Fluid pressure = 1123.6 pounds/ square inch

Thu, the fluid pressure in the jack at maximum load is 1123.6 pounds/ square inch.

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Dos capacitores de placas paralelas, idénticos, pero con la excepción de que uno tiene el doble de separación entre sus placas q
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Las características de la capacitancia permiten encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es  

             C = \frac{Q}{DV} = \frac{\epsilon_o A}{d}  

Donde Q es a carga, ΔV la diferencia de potencial, A el area y d la separación de las placas.

Busquemos las respuestas para las diferentes preguntas:

1) Cual tiene mayor campo eléctrico.

El potencial y el campo eléctrico están relacionados

            ΔV = - E d

            E = - \frac{\Delta V}{d}

Indican que un capacitor tiene el doble de separación de las placas que el otro

Capacitor 1

          E = - \frac{\Delta V}{d_1}  

Capacitor 2

         d₂ = 2 d₁  

         E₂ = - \frac{\Delta V}{2d_1}  

         E₂= ½ E₁

Por lo tanto el capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) Cual tiene mas carga

Busquemos la carga para cada capacitor  

           Q = ε₀ \frac{A \Delta V}{d}  

Capacitor 1

           Q₁ = (ε₀ A ΔV) \frac{1}{d_1}

Capacitor 2

           Q₂ = (ε₀ A Δv) \frac{1}{2d_1}

           

            Q₂ = Q₁/2

       

El capacitor con menor distancia tiene mayor carga

3) Cual tiene mayor densidad de energía

La densidad de energía en un capacitor esta dada por

         u_E  = ½ ε₀ E²  

calculamos para cada capacitor

           

Capacitor 1

         u_{E\  1} = ½ ε₀ E₁²

Capacitor 2

         u_{E 2} = ½ ε₀ (E₁/2)²

por lo cual el capacitor con menor distancia tiene mas densidad de carga

En conclusión con lass característica de capacitancia podemos encontrar los resultados para las diferentes preguntas

     1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

    2) El capacitor con menor distancia tiene mayor carga

    3) El capacitor con menor distancia tiene mas densidad de carga  

Aprender mas aquí:  brainly.com/question/22813371

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