Answer:
Not too far removed from Collingwood’s concern with the elimination of physical and moral force via social civilization are accounts of civilized society concerned with the management of violence, if only by removing it from the public sphere. Such a concern is extended in Zygmunt Bauman’s account of civilization to the more general issue of producing readily governable subjects. The “concept of civilization,” he argues, “entered learned discourse in the West as the name of a conscious proselytising crusade waged by men of knowledge and aimed at extirpating the vestiges of wild cultures” (1987, 93).
This proselytizing crusade in the name of civilization is worth considering further. Its rationale is not too difficult to determine when one considers Starobinski’s (1993, 31) assertion: “Taken as a value, civilization constitutes a political and moral norm. It is the criterion against which barbarity, or non-civilization, is judged and condemned.” A similar sort of argument is made by Pagden (1988, 33), who states that civilization “describes a state, social, political, cultural, aesthetic—even moral and physical—which is held to be the optimum condition for all mankind, and this involves the implicit claim that only the civilized can know what it is to be civilized.” It is out of this implicit claim and the judgments passed in its name that the notion of the “burden of civilization” was born. And this, many have argued, is one of the less desirable aspects and outcomes of the idea of civilization
Answer:
Explanation:
The politropic relationship for a isentropic process is:
Where 
is the ratio of specific heats
The final pressure is:
Answer:
The algorithm is as follows:
1. Declare Arr1 and Arr2
2. Get Input for Arr1 and Arr2
3. Initialize count to 0
4. For i in Arr2
4.1 For j in Arr1:
4.1.1 If i > j Then
4.1.1.1 count = count + 1
4.2 End j loop
4.3 Print count
4.4 count = 0
4.5 End i loop
5. End
Explanation:
This declares both arrays
1. Declare Arr1 and Arr2
This gets input for both arrays
2. Get Input for Arr1 and Arr2
This initializes count to 0
3. Initialize count to 0
This iterates through Arr2
4. For i in Arr2
This iterates through Arr1 (An inner loop)
4.1 For j in Arr1:
This checks if current element is greater than current element in Arr1
4.1.1 If i > j Then
If yes, count is incremented by 1
4.1.1.1 count = count + 1
This ends the inner loop
4.2 End j loop
Print count and set count to 0
<em>4.3 Print count</em>
<em>4.4 count = 0</em>
End the outer loop
4.5 End i loop
End the algorithm
5. End
One of the methods that are used to separate polymers, aluminium alloys, and steels from one another is the Gravitation Separation method.
One straightforward technique is to run the mixture through a magnet, which will keep the steel particles on the magnet and separate them from the polymer.
What is the Gravitation Separation method?
When it is practicable to separate two components using gravity, i.e., when the combination's constituent parts have different specific weights, gravity separation is a technique used in industry. The components can be in suspension or in a dry granular mixture.
Polymers, Steel and Aluminium alloys can be readily split apart. The technique depends on how the two components are combined. The approach used is gravitational density. Due to the significant difference in relative specific mass values between steel and polymers (which range from 1.0 to 1.5), it is possible to separate them using flotation in a liquid that is safe and has the right density.
Therefore, the Gravitation Separation method is used to separate polymers, aluminium alloys and steels.
To learn more about the Polymer from the given link
brainly.com/question/2494725
#SPJ4
Answer:
Q= 6491.100 kJ/s
Explanation:
Air-Fuel Ratio:
For a combustion reaction the proportion of air that is present in a gaseous substance responsible for the reaction,this proportion is known as air-fuel ratio.The air fuel ratio is calculated using the combustion reaction for the substance.
Considering reaction for the Ethanol as
C₂H₅OH +XO₂(O₂+3.76N₂)→ aCO₂+bH₂O+cN₂
Balancing the equation we get;
a=2,
2b=6
∴ b=3
xO₂=3
The air-fuel ratio
A/F = XO₂+H₂O+xN₂× mass of N₂/mass(fuel)
3.31×31.9+11.28×28.013/46.069
= 8.943
Equivalent ratio = 0.7,
so, heat transfer
Q= m ×Cp×ΔT
= 75×0.7×112.4(1500-400)
Q= 6491.100 kJ/s
1kJ/s=1000w
∴ Q= 6491100 W
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