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kherson [118]
3 years ago
5

Gtjffs

Engineering
1 answer:
grandymaker [24]3 years ago
4 0

the required documents is 3000

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Brittle failure is a type of failure in which: (a) There is large amount of plastic deformation (b) Large amount of elastic defo
sp2606 [1]

Answer:

    c). Very little plastic and elastic deformation

Explanation:

Brittle failure is a sudden, very rapid crack where there is no sign of any plastic deformation or ductility. The failure is not stable unlike ductile failure and the the crack propagates very fast without any further increase of any stress. In brittle failure there is very little plastic deformation and low energy is absorbed before fracture takes place.

Thus, very little plastic and elastic deformation takes place in brittle failure.

7 0
3 years ago
Which option demonstrates what will happen once a prototype is developed
Xelga [282]

Answer:

just free your mind drink water and go outside take fresh air you will get answers.

Explanation:

This a best method to solve the answer.I hope it is helpful

8 0
4 years ago
What do electrons have to do with electrical current?
erastova [34]

Answer:

Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity.

6 0
4 years ago
What is the normal balance side of an asset?
Mademuasel [1]
The normal balance for asset and expense accounts is the debit side, while for income, equity, and liability accounts it is the credit side. An account's assigned normal balance is on the side where increases go because the increases in any account are usually greater than the decreases
8 0
3 years ago
A box of mass m = 4 kg is suspended vertically from a spring with stiffness k = 64 N/m. Determine the position of the box as a f
Hatshy [7]

Answer:

x=0.5 sin 4 t

Explanation:

Given that:

mass m = 4 kg

Stiffness K =64 N/m

Given spring mass system will be in simple harmonic motion.We know that in simple harmonic motion the natural frequency given as follows

\omega _n=\sqrt{\dfrac{K}{m}}

Now by putting the values

\omega _n=\sqrt{\dfrac{64}{4}}

\omega _n=4 rad/s

The equation of SHM given as

\ddot{x}+\omega _n^2x=0

The solution of above equation will be

x=Asin\omega _nt

x=A sin 4 t

Given at t=0 ,V= 2 m/s

So

V= 4 A cos 4 t

2 = 4 A

A= 0.5

The equation  of motion will be

x=0.5 sin 4 t

3 0
3 years ago
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