All categories

3 years ago

What is the primary function of NCEES?

Engineering

1 answer:

joja [24]3 years ago

7 0

National Council of Examiners for engineering and surveying a nonprofit organization

You might be interested in

If the old radiator is replaced with a new one that has longer tubes made of the same material and same thickness as those in th

Nookie1986 [14]

Answer: hello some parts of your question is missing attached below is the missing information

The radiator of a car is a type of heat exchanger. Hot fluid coming from the car engine, called the coolant, flows through aluminum radiator tubes of thickness d that release heat to the outside air by conduction. The average temperature gradient between the coolant and the outside air is about 130 K/mm . The term ΔT/d is called the temperature gradient which is the temperature difference ΔT between coolant inside and the air outside per unit thickness of tube

answer : Total surface area = 3/2 * area of old radiator

Explanation:

we will use this relation

K = $\frac{Qd }{A* change in T }$

change in T = ΔT

therefore New Area ( A ) = 3/2 * area of old radiator

Given that the thermal conductivity is the same in the new and old radiators

3 0

3 years ago

The advantage of using rose bud tips is that they:

Jlenok [28]

Answer:

The advantage to using a rosebud tip is that it expands the flame temperature over a wider area vs using a #0 size tip.

Explanation:

Hope this helped Mark BRAINLIEST!!

3 0

2 years ago

After a strong storm, a worker does not realize that a power transmission line has fallen on his car and is electrocuted while o

joja [24]

Answer and Explanation:

The correct answer choice is Contacting Overhead Power Lines.

This is because the powerlines are making contact (touching) his car, and the example isn't related to the other answer choices.

#teamtrees #PAW (Plant And Water)

3 0

2 years ago

5. A pump operating at steady state receives 1.2 kg/s of liquid water at 50o C, 1.5 MPa. The pressure of the water at the pump e

Andrew [12]

Answer:

the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW

the isentropic pump efficiency is 78%

Explanation:

Given that;

m = 1.2 kg/sec

T = 50 degree Celsius { Vf = 0.001012 m^3/kg}

P1 = 1.5 Mpa

P2 = 15 Mpa

W-actual = 21 kw

W reversible = m*Vf (p2 - p1)

= 1.2 * 0.001012 * ( 15*10^3 - 1.5*10^3)

= 1.2 * 0.001012 * 13500

= 16.39 kW

the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW

Isentropic Pump efficiency = W-reversible / W-actual

= 16.39 / 21 = 0.78

= 78%

the isentropic pump efficiency is 78%

6 0

3 years ago

Viteza unui mobil care se deplasează cu accelerație constantă crește de la 3,2 m/s la 5,2 m/s în timp de 8 s. Accelerația mobilu

Verizon [17]

Answer:

$a=0.25\ m/s^2$

Explanation:

Initial speed of the mobile = 3.2 m/s

Final speed of the mobile = 5.2 m/s

Time, t = 8 s

We need to find the acceleration of the mobile. It can be given by the change in velocity divided by time. So,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{(5.2-3.2)\ m/s}{8\ s}\\\\=0.25\ m/s^2$

So, the acceleration of the mobile is $0.25\ m/s^2$ .

3 0

3 years ago