Explanation:
u = 13m/s
s = 36.2m
a = 9.81m/s² (positive because it is acting on the same direction as the velocity)
Using Kinematics, we have v² = u² + 2as = (13)² + 2(9.81)(36.2) = 879.244m²/s². => v = 29.65m/s.
The channel is whatever was used to carry information from
one place to another, or from one person to another.
In this scenario, the channel is e-mail.
Answer: 1. higher than it was before they started running
Explanation: As the vacationers run towards the back(stern) of the ship the exerting more pressure against the pressure exerted by the wave supporting the moving ship,the pressure exerted on the moving ship will be increased, leading to a slight increase in the speed of the ship compared to the speed before they started running towards the back(stern) of the ship.
Answer:
<h3>The answer is 6 m/s²</h3>
Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula
where
v is the velocity
t is the time
We have
We have the final answer as
<h3>6 m/s²</h3>
Hope this helps you
Answer:
A) 35 ft
B) 5 ft
C) Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick
Explanation:
A) Total distance covered by the dog = 20 + 15
= 35 ft
B) Since the other distance covered by the dog before chewing the stick, after the retrieval, was in an opposite direction to the initial direction, then;
total displacement of the dog = 20 - 15
= 5 ft
C) Net displacement = distance covered by the dog to retrieve the stick + distance covered before the dog starts chewing the stick
But, displacement involves a specified direction. The distance covered before the dog starts chewing the stick was in an opposite direction to the initial direction.
Thus,
Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick
