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svp [43]
3 years ago
15

describe how you can use a compass needle to determine the direction of a magnetic field at a given location

Physics
1 answer:
Solnce55 [7]3 years ago
8 0

The compass doesn’t give you the value of the net magnetic field, just the direction. So, how do you get the magnitude of a particular field from this? The trick is to assume the value of the Earth’s magnetic field and the direction of the compass. Let’s assume that at this location on the Earth, the magnetic field is pointing directly North with a horizontal component of about 2 x 10-5 T.

Now suppose that I do something to create a magnetic field in a known direction and perpendicular to the horizontal component of the Earth’s magnetic field. Here is an example where I put a current carrying wire right over the compass needle. Since the compass is underneath the wire, the magnetic field due to the wire will be 90° to the Earth’s magnetic field.

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Which of the following is a list of
KonstantinChe [14]

Answer:

c. metallic, sub metallic, or nonmetallic

4 0
3 years ago
5. A stream of air at 12 bar and 900 K is mixed with another stream of air at 2 bar and 400 K with 2 times the mass flowrate. If
Softa [21]

Answer:

The anserrs to the question are

(a)  The temperature would be 566.67  K and

(b) The pressure of the resulting air stream is 14 bar

Explanation:

Here the two streams of gases meet ad form a single stream

The steady-flow energy equation can be implemented at the mixing point of the to streams as follows

mₐhₐ₁ + mₙ hₙ₁ + Q° + W° = mₐhₐ₂ + mₙhₙ₂

Where the flow is adiabatic, we have

Q = 0 and  W = 0  hence

mₐhₐ₁ + mₙ hₙ₁ = mₐhₐ₂ + mₙhₙ₂ where h = cp×T we have

mₐcpₐ×Tₐ + mₙcpₙ×Tₙ  = mₐcpₐ×T + mₐcpₙ×T

Therefore the final temperature T is given by

T = \frac{m_ac_{pa}T_a + m_nc_{pn}T_n}{m_ac_{pa} + m_nc_{pn}}  for the same kind of gas cpₐ =cpₙ therefore

T = \frac{m_aT_a + m_nT_n}{m_a + m_n} where mₐ and mₙ are mass flow rate

Therefore we have where Tₐ = = 900 K and Tₙ = 400 K and mₙ = 2mₐ gives

T = \frac{m_a*900 + 2*m_a*400}{m_a + 2*m_a} = T = \frac{900 + 800}{1 + 2} = 1700/3 = 566.67 K  

From Dalton's law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the components of the mixture

Therefore the total pressure of the combined stream = pₐ + pₙ = p

= 12 bar + 2 bar = 14 bar

Stream pressure = 14 bar

4 0
3 years ago
English schoolteacher who proposed the atomic theory model of matter
vodka [1.7K]

Answer:

Ernest Rutherford.

Explanation:

Ernest Rutherford

4 0
3 years ago
A catcher catches a 150g baseball traveling horizontally at 25 m/s. If the ball takes 20.ms to stop once it is in contact with t
rosijanka [135]

Answer:

The magnitude of the force exerted by the ball on the catcher is 1.9 × 10²  N

Explanation:

Hi there!

Let´s find the acceleration of the ball that makes it stop when caught by the catcher. The acceleration can be calculated from the equation of velocity considering that it is constant:

v = v0 + a · t

We know that initially the ball was traveling at 25 m/s, so, if we consider the position of the catcher as the origin of the frame of reference, then, v0 = -25 m/s. We also know that it takes the ball 20 ms (0.02 s) to stop (i.e. to reach a velocity of 0). Then using the equation of velocity:

v = v0 + a · t

0 m/s = -25 m/s + a · 0.020 s

25 m/s/ 0.020 s = a

Now, using the second law of Newton, we can calculate the force exerted by the catcher on the ball:

F = m · a

Where:

F = force.

m = mass of the ball.

a = acceleration.

F = 0.150 kg · (25 m/s/ 0.020 s) = 1.9 × 10²  N

According to Newton´s third law, the force exerted by the ball on the catcher will be of equal magnitude but opposite direction. Then, the force exerted by the ball on the catcher will have a magnitude of 1.9 × 10²  N.

3 0
4 years ago
How was the earth formed
liubo4ka [24]

Answer: Earth formed when gravity pulled swirling gas and dust in to become the third planet from the Sun. Like its fellow terrestrial planets, Earth has a central core, a rocky mantle and a solid crust

5 0
3 years ago
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