Given:
The force of attraction is F = 48.1 N
The separation between the charges is
Also, the magnitude of charge q1 = q2 = q.
To find the magnitude of charge.
Explanation:
The magnitude of charge can be calculated by the formula
Here, k is the Coulomb's constant whose value is
On substituting the values, the magnitude of charge will be
Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.
Answer:
.5 units north
<em><u>or</u></em>
55 ft/minutes(<em>squared</em>) north
Explanation:
.5 is what your info gives me but if i take that the average distance a block is it is 660ft than the answer is 55.
The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1) </span>
= 0.414L
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
Hello!
Answer:
When a gas gets hot it should go up because of the pressure.
Explanation:
Hope this helps!
Answer:
1). Average speed = 1.5 m per second
2). Average velocity = 1.5 m per second
Explanation:
1). Since, speed is a scalar quantity
Therefore, average speed of the trip =
From the graph attached,
Total distance covered = 10 + 10 + 20 + 0 + 20 + 30
= 90 meters
Total time taken = 60 seconds
Average speed =
= 1.5 meter per second
2). Velocity is a vector quantity.
Therefore, average velocity =
=
=
= 1.5 meter per second