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maks197457 [2]
3 years ago
8

if 0.00327 g of a gas dissolves in 0.376 L of water at 867 torr, what quantity of this gas (in grams) will dissolve at 759 torr?

Chemistry
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

0.00286

Explanation:

Hope this helps!

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5) Determine the mass if lithium hydroxide that is produced when 12.87 g of lithium
netineya [11]

Answer: 26.54 grams

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of lithium nitride}=\frac{12.87g}{34.83g/mol}=0.369moles

Li_3N+3H_2O\rightarrow 3LiOH+NH_3  

Li_3N is the limiting reagent as it limits the formation of product and H_2O is the excess reagent

According to stoichiometry :

As 1 moles of Li_3N give = 3 moles of LiOH

Thus 0.369 moles of O_2 give =\frac{3}{1}\times 0.369=1.108moles  of LiOH

Mass of LiOH=moles\times {\text {Molar mass}}=1.108moles\times 23.95g/mol=26.54g

Thus  26.54 g of LiOH will be produced from the given mass.

4 0
3 years ago
Please help , science tho. by the way i have to do 5
kap26 [50]

Answer:

850

Explanation:

It's between 840 and 860

8 0
2 years ago
What elements can join wit other elements o form a covalent bond
Bas_tet [7]

Answer:

Non metals join to form covalent bond.

Explanation:

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

Both atoms bonded through covalent bond.

In Cl₂ both chlorine atoms are bonded through the covalent bond.

8 0
3 years ago
Please answer number 2
alexandr402 [8]

Answer:

A

Explanation:

Because Rainwater can get acidic because of the carbonic acid that it contains

8 0
3 years ago
Part 1. A chemist reacted 18.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
Alika [10]

Answer:

Part 1

The mass of the NaCl that reacted with F₂ at 290.K and 1.5 atm is approximately 132.6 gams

Part 2

The mass of NaCl that can react with the same volume of gas at STP is approximately 93.77 grams

Explanation:

Part 1

The volume of F₂ gas in the reaction, V = 18.0 liters

The ideal gas equation is P·V = n·R·T

∴ n = P·V/(R·T)

The pressure, P = 1.5 atm

The temperature, T = 290 K

The universal gas constant, R = 0.0820573 L·atm/(mol·K)

∴ n = 1.5×18/(0.0820573 × 290) ≈ 1.134615

The number of moles of F₂ in the reaction n ≈ 1.134615 moles

The chemical reaction is given as follows;

F₂ + 2NaCl → Cl₂ + 2NaF

1 mole of F₂ reacts with 2 moles of NaCl

Therefore;

1.134615 moles of F₂ reacted with 2 × 1.134615 moles ≈ 2.26923 moles of NaCl

1 mole of NaCl = The molar mass of NaCl, MM = 58.44 g/mol

The mass, of 2.26923 moles of NaCl, m = Number of moles × MM

∴ m ≈ 2.26923 moles × 58.44 g/mol ≈ 132.6 grams

The mass of the NaCl ≈ 132.6 gams

Part 2

The volume occupied by 1 mole of all gases at STP = 22.4 l/mole

Therefore, the number of moles of F₂ in 18.0 L of F₂ = 18.0 L/(22.4 L/mole) ≈ 0.804 moles

Therefore;

The number of moles of NaCl, in the reaction n = 2 × The number of moles of F₂ ≈ 2×0.804 moles = 1.608 moles

The number of moles of NaCl, in the reaction n ≈ 1.608 moles

The mass of NaCl in the reaction, m = n × MM

∴ m ≈ 1.608 moles × 58.44 g/mol ≈ 93.97 grams

The mass of NaCl that can react with the same volume of gas at STP ≈ 93.77 grams

8 0
3 years ago
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