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mamaluj [8]
2 years ago
14

How does using the straw demonstrate “point of application” of a force?

Physics
2 answers:
aliina [53]2 years ago
5 0

Answer:it is the exact location of something.

Explanation:

Likurg_2 [28]2 years ago
5 0
It depends where the location is
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A wave has a velocity of 24 m/s and a period of 3.0 s. Calculate the wavelength of the wave.
Katyanochek1 [597]

Velocity (unit:m/s) of the wave is given with the formula:

v=f∧,

where f is the frequency which tells us how many waves are passing a point per second (unit: Hz) and ∧ is the wavelength, which tells us the length of those waves in metres (unit:m)

f=1/T , where T is the period of the wave.

In our case: f=1/3

∧=v/f=24m/s/1/3=24*3=72m

5 0
3 years ago
Calculate the constant acceleration a in g’s which the catapult of an aircraft carrier must provide to produce a launch velocity
goblinko [34]
The solution to the problem is as follows:

<span>First, I'd convert 188 mi/hr to ft/s. You should end up with about ~275.7 ft/s.
 
So now write down all the values you know:

Vfinal = 275.7 ft/s

Vinitial = 0 ft/s

distance = 299ft
</span>
<span>Now just plug in Vf, Vi and d to solve
</span>
<span>Vf^2 = Vi^2 + 2 a d 

</span><span>BTW: That will give you the acceleration in ft/s^2. You can convert that to "g"s by dividing it by 32 since 1 g is 32 ft/s^2.</span>
5 0
2 years ago
Who is the first person to trace the characteristics of successive generations of a living thing?
Andrei [34K]
Gregor Mendel was the first person to trace the characteristics of successive generations of a living thing.
7 0
3 years ago
Read 2 more answers
Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floa
zloy xaker [14]

Answer:

the position of the wood below the interface of the two liquids is 2.39 cm.

Explanation:

Given;

density of oil, \rho _o = 926 kg/m³

density of the wood, \rho _{wood} = 974 kg/m³

density of water, \rho _w = 1000 kg/m³

height of the wood, h = 3.69 cm

Based on the density of the wood, it will position across the two liquids.

let the position of the wood below the interface of the two liquids = x

Let the wood be in equilibrium position;

F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood}  -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood}  -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

6 0
3 years ago
The removal of rock in solution by acidic rain water________​
Veronika [31]

Answer:

Solution

Explanation:

Solution is a process in chemical weathering and it is the process of dissolving or removing rock in a solution through the activities of acid rain or solution. Chemical weathering refer to the process where rocks interact with chemical solutions or acid rain which can result in His integration.

3 0
2 years ago
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