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larisa86 [58]
2 years ago
12

What does a negative acceleration mean if the object has positive velocity?

Physics
2 answers:
Sedaia [141]2 years ago
3 0

Answer:

An object which moves in the positive direction has a positive velocity.  If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion .  If velocity and acceleration have opposite signs, you slow down. Negative velocity = You move backwards. Negative acceleration - You slow down or you go faster in the backwards direction

Explanation:

Blizzard [7]2 years ago
3 0

Explanation:

An object which moves in the positive direction has a positive velocity.

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion aka negative velocity.

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How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?
gtnhenbr [62]

Answer:

W = 47040  J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040  J

So, the required work done is 47040  J.

7 0
3 years ago
A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

f_n=\frac{nv_s}{4L}

n: number of the harmonic = 3

vs: speed of sound = 340 m/s

L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

hence, the frequency of the third overtone is 102 Hz

8 0
3 years ago
How many newtons of force are represented by the following amount: 3 kg·m/sec^2?
Jet001 [13]
1N=1kg•m/s^2 so the answer is 3N
8 0
3 years ago
Find an expression for the kinetic energy of the car at the top of the loop.Express the kinetic energy in terms of m, g, h, and
lyudmila [28]

Answer:

K.E₂ = mg(h - 2R)

Explanation:

The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:

K.E₁ + P.E₁ = K.E₂ + P.E₂

where,

K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)

P.E₁ = Initial Potential Energy = mgh

K.E₂ = Final Kinetic Energy at the top of the loop = ?

P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)

Therefore,

0 + mgh = K.E₂ + mg(2R)

<u>K.E₂ = mg(h - 2R)</u>

3 0
3 years ago
F-40N<br>m=5k<br>k = 0,2<br>a=? <br><br><br>​
tester [92]

Answer:

1......... .......... ......

3 0
3 years ago
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