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2 years ago

What does a negative acceleration mean if the object has positive velocity?

Physics

2 answers:

Sedaia [141]2 years ago

3 0

Answer:

An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion . If velocity and acceleration have opposite signs, you slow down. Negative velocity = You move backwards. Negative acceleration - You slow down or you go faster in the backwards direction

Explanation:

Blizzard [7]2 years ago

3 0

Explanation:

An object which moves in the positive direction has a positive velocity.

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion aka negative velocity.

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2 years ago

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An 800 N man stands on a scale in a motionless elevator. When the elevator begins to move, the scale

DENIUS [597]

Answer:

Net force = 800 – 650

= 150 N

150 = (800 ÷ 9.8) a

a = 1470 ÷ 800

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2 years ago

A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15°, and rolls to the bottom. The

cluponka [151]

Answer:

v = 4.1 m/s

Explanation:

As per mechanical energy conservation law we can say that initial total gravitational potential energy of the sphere is equal to final kinetic energy of rolling

so we will say

$mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$

now for pure rolling condition we know that

$v = R\omega$

so we will have

$mgh = \frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{5}mR^2)(\frac{v^2}{R^2})$

$mgh = \frac{7}{10}mv^2$

now we will have

$v^2 = \sqrt{\frac{10}{7}gh}$

$v^2 = \sqrt{\frac{10}{7}(9.8)(1.2)}$

$v = 4.1 m/s$

7 0

2 years ago

13. A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V a

Lisa [10]

Answer:

The output power is 2 kW

Explanation:

It is given that,

Number of turns in primary coil, $N_p=250$

Number of turns in secondary coil, $N_s=500$

Voltage of primary coil, $V_p=200\ V$

Current drawn from secondary coil, $I_s=5\ A$

We need to find the power output. It is equal to the product of voltage and current. Firstly, we will find the voltage of secondary coil as :

$\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}$

$\dfrac{250}{500}=\dfrac{200}{V_s}$

$V_s=400\ V$

So, the power output is :

$P_s=V_s\times I_s$

$P_s=400\ V\times 5\ A$

$P_s=2000\ watts$

$P_s=2\ kW$

So, the output power is 2 kW. Hence, this is the required solution.

8 0

3 years ago

In a circuit, the supplied voltage is 1.5 volts, and the resistor value is 3 ohms. What is the current in the circuit?

pogonyaev

Using Ohm's Law:

V = IR

Where V = Voltage in Volts, I = Current in Ampere, R = Resistance in Ohms

V = IR

1.5 = I * 3

1.5 = 3I

3*I = 1.5

I = 1.5/3

I = 0.50 A

Current in the Circuit is 0.50 Ampere.

6 0

2 years ago