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larisa86 [58]
2 years ago
12

What does a negative acceleration mean if the object has positive velocity?

Physics
2 answers:
Sedaia [141]2 years ago
3 0

Answer:

An object which moves in the positive direction has a positive velocity.  If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion .  If velocity and acceleration have opposite signs, you slow down. Negative velocity = You move backwards. Negative acceleration - You slow down or you go faster in the backwards direction

Explanation:

Blizzard [7]2 years ago
3 0

Explanation:

An object which moves in the positive direction has a positive velocity.

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion aka negative velocity.

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It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time (\Delta t)

I=F \Delta t

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

I=(ma) \Delta t

However, the acceleration is the ratio between the change in velocity (\Delta v) and the contact time (\Delta t): a=\frac{\Delta v}{\Delta t}, so the previous equation becomes

I=m \frac{\Delta v}{\Delta t}\Delta t

And by simplifying \Delta t,

I=m \Delta v

which corresponds to the change in momentum of the object.

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3 years ago
What type of force act on a man at room temperature and in a ground?
lakkis [162]
Isaac Newton’s second law of motion
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3 years ago
Part of understanding the physical effects on Mars, we must understand
Ber [7]

Answer:

so easy add the subtract then multiplay the add

Explanation:

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3 years ago
The teacher shared a demonstration with the same students. She begin by standing on a desk, holding a book and an open piece of
bazaltina [42]

Answer:

I think its c

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7 0
3 years ago
Two long straight parallel lines of charge, #1 and #2, carry positive charge per unit lengths of λ1 and λ2, respectively. λ1 &gt
Stella [2.4K]

Answer:

Somewhere between the two wires, but closer to the wire carrying λ₂

Explanation:

Electric Field for a point at distance x from an electric charge Q is Ef = K*Q/x².

Electric Fied due to an electric charge is a vector and its direction is  such that  if we place a positive charge in the point it will be rejected ( equal sign charge repulse each other and different attract each other)

According to that previous explanation, it is no possible two have Ef=0 out of the two wires region, since above the upper wire and below the lower wire we have to add the two electric fields (both have the same direction). Therefore we only have possibilities of Ef = 0 inside the two wires, where the repulsion produced over a positive charge due to the two wires  are opposite

In the particular case in which λ₁ and λ₂ are equals then all the points exactly in the middle of d (distance between the two wires ) will have Ef =0.

As we can see at the beginning of the step by step explanation Electric field is proportional to the electric charge, or for a bigger charge, bigger Ef (keeping constant distance). In our case λ₁ >λ₂ then E₁ (Electric field produced by a wire carrying λ₁ will be bigger than (Electric field produced by wire carrying λ₂ at the middle way between the wires.

But for points closer to wire with λ₂  ( where E₂ is bigger than E₁ ) we will surely find an appropriate distance  to get equals E and then Ef = 0

3 0
2 years ago
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