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docker41 [41]
2 years ago
9

Laura adds 50mL of boiling water to 100mL of ice water. If the 150 mL of water is then put into a freezer, at what temperature w

ill the water freeze?
Physics
1 answer:
Dennis_Churaev [7]2 years ago
8 0
Water that is pure, will always freeze at 0 degrees.
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In the absence of a gravitational force, the weight of a body is?
azamat

Answer:

0

Explanation:

Weight = mass x gravity

if gravity = 0 then Weight =0 as well

5 0
2 years ago
What temperature will 1L of H20 at 200°F become when a piece of copper,0.25kg at 260.928K, comes into contact with water?
Lady_Fox [76]

Answer:

Explanation:

mass of 1 L water = 1 kg .

200⁰F = (200 - 32) x 5 / 9 = 93.33⁰C .

260.928 K = 260.928 - 273 = - 12.072⁰C .

water is at higher temperature .

Let the equilibrium temperature be t .

Heat lost by water = mass x specific heat x  fall of temperature

= 1 x 4.2 x 10³ x ( 93.33 - t )

Heat gained by copper

= .25 x .385 x 10³ x ( t +  12.072 )

Heat lost = heat gained

1 x 4.2 x 10³ x ( 93.33 - t ) = .25 x .385 x 10³ x ( t +  12.072 )

93.33 - t = .0229 ( t + 12.072)

93.33 - t = .0229 t + .276

93.054 = 1.0229 t

t = 90.97⁰C .

7 0
2 years ago
for a certain chemical reaction, the reactants contain 52 kj of potential energy and the products contain 32 kj how much energy
Luden [163]
B, is the answer. (20 kj is released)
7 0
2 years ago
Read 2 more answers
A 100-g aluminum calorimeter contains 500 g of water at a temperature of 20ºC. Then a 140-g piece of metal, initially at 344ºC,
Lunna [17]
601 J/kg the answer is
3 0
2 years ago
Please help me
Grace [21]

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

6 0
2 years ago
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