Answer:
740 N
Explanation:
We are given that
Radius,r=0.3 m
Torque,
We have to find the magnitude of the static frictional force.
According to question
Torque by engine=Torque by static friction
Hence, the magnitude of static frictional force=740 N
Answer:
To investigate into how the height of a ramp affects the speed of a toy car rolled down a hill or slope because the higher the ramp the more Gravitational potential Energy (GPE), the more kinetic energy converted and the car will go faster. So the ramp increases, the velocity will also increase.
Explanation:
Answer:
Explanation:
mass of the alloy = 35.2 g
temperature t of the alloy = 93° C
heat loss by alloy = mc ( t₁ - t₂) where t₁ = 93 and t₂ = 31.1° C
heat loss by alloy = 2178.88 c where c is the specific heat capacity of the alloy
heat gained by water = m cw ( t₂ - t₁ ) where t₁ of water = 22° C and t₂ of water = 31.1° C
heat gained by water = 8338.294
heat gained = heat loss
2171.84 c = 8338.294
c specific heat capacity of the alloy = 8338.294 / 2178.88 = 3.83 J/g.K
<h2>When a mass on a spring that has been compressed 0.1 m has a restoring force of 20 N , then the value of spring constant (k) :- </h2><h2>200 N/m</h2>
Explanation:
Spring Constant :
According to Hooke's law, The force required to compress or extends spring is directly proportional to the distance it is compressed or stretched.
Given
x = -0.1 m
F = 20 N
F - -kx
k = -f/x
= -20 / -0.1 = 200 N/m
The value of spring constant is 200 N/m.
