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tensa zangetsu [6.8K]
3 years ago
8

When a massive star greater than 8 solar masses has its core filled with iron, the core can no longer continue fusion, and it be

comes supported by electron degeneracy pressure for a while. When the mass of the accumulating iron becomes greater than 1.4 solar masses, what happens
Physics
1 answer:
Musya8 [376]3 years ago
4 0
I know if honest at this point right
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In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=
swat32

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.

<h3>Where is the electric potential, when the particle moved?</h3>

The charge field system's electric potential energy rose. The particle experiences an electric force that is directed against the x-axis. It is pushed uphill by an outside force, which raises the potential energy.

When a charge to be moved against an applied electric field, electric potential energy is needed. A charge must be moved through a stronger electric field with more energy than it would require to carry it via a weaker electric field.

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.

The electric potential energy of the charge field system:

  • (a) increase
  • (b) remain constant
  • (c) decrease
  • (d) change unpredictably

The correct option is a).

To learn more about electric potential, refer to:

brainly.com/question/21808222

#SPJ4

7 0
2 years ago
7. Two bikes travelling in the same direction move at a speed of 30 km/hr. The bikes are separated by a distance of 5 km. What w
Fantom [35]

Answer:

Explanation:

Call the bike on the right A

Call the bike on the left B

The car begins it's time when it passes A

4 minutes later, it passes B.

But B has moved in 4 minutes and that is the key to the problem.

How far has B moved.

t = 4 minutes = 4/60 hours = 1/15 of an hour.

d = ?

rate = 30 km / hr

d = r * t

d = 30 km/hr * 1/15 hours = 2 km

The distance between the bikes is 5 km.

So the car has traveled 5 - 2 = 3 km

d = 3 km

r = ?

t = 4 minutes = 1/15 hour

r = d/t = 3/(1/15)= 3 / 0.066666666  = 45 km/hr.

6 0
4 years ago
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
Does water have mass? How do you know?
Bess [88]

every thing on this earth has it,s own mass

8 0
4 years ago
Read 2 more answers
On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 81.7 cm and diameter 2.70 cm fr
Genrish500 [490]

Answer:

35.792 N

Explanation:

d = Diameter of rod = 2.7 cm

h = Length of rod = 81.7 cm

\rho = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

V=\dfrac{1}{4}\pi d^2h\\\Rightarrow V=\dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}

Mass is given by

m=\rho V\\\Rightarrow m=7800\times \dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}\\\Rightarrow m=3.6486\ kg

Weight is given by

W=mg\\\Rightarrow W=3.6486\times 9.81\\\Rightarrow W=35.792\ N

The weight of the rod is 35.792 N

7 0
3 years ago
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