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4 years ago

In which type of wave do air particles move together or apart parallel to the direction of the wave?

1 answer:

8 0

The best and most correct answer among the choices provided by the question is <span>B.sound waves</span><span>.
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<span>Particles move together or apart parallel to the direction of the sound wave.
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Hope my answer would be a great help for you.
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A chemical reaction takes place in which energy is absorbed. Arrange the characteristics of the reaction in order from start to

Ira Lisetskai [31]

<h2>Answer</h2>

It will be single step endothermic reaction.

<h2>Expalantion</h2>

In the endothermic reaction, the reactants come together to convert to products by absorbing the heat from the external source. This reaction is explained is also known as one step reaction as reactants meet to get the transition stage and converts to the product. But in some reactions, the activation energy required to activate the reactants to get the transition stage to form products. For this, the reaction will have the steps as activation energy, reactant meet, transition stage and products form.

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3 years ago

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Six artificial satellites complete one circular orbit around a space station in the same amount of time. Each satellite has mass

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The satellites launch rockets to generate the force required to keep an orbit all around space station circular. The continuous centripetal force is maintained by the centripetal force.

<h3>What is a good illustration of gravity?</h3>

The energy holding the gases inside the sun. the power behind a ball's descent after being thrown into the air. the force that makes an automobile coast downward even when the gas is not depressed.

<h3>What makes anything gravitational?</h3>

Our term gravity and more specific derivation gravitation are derived from a Latin word gravity, from gravis, which itself is derived from a much older root word that is considered to have existed due to multiple cognates in closely related languages.

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1 year ago

Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m

netineya [11]

Answer: $m \frac{d}{dt}v_{(t)}$

Explanation:

In the image attached with this answer are shown the given options from which only one is correct.

The correct expression is:

$m \frac{d}{dt}v_{(t)}$

Because, if we derive velocity $v_{t}$ with respect to time $t$ we will have acceleration $a$ , hence:

$m \frac{d}{dt}v_{(t)}=m.a$

Where $m$ is the mass with units of kilograms ( $kg$ ) and $a$ with units of meter per square seconds $\frac{m}{s}^{2}$ , having as a result $kg\frac{m}{s}^{2}$

The other expressions are incorrect, let’s prove it:

$\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)}$ This result has units of $kg\frac{m}{s}$

$m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m$ This result has units of $kg$

$m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C$ This result has units of $kgm^{2}$ and $C$ is a constant

$m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m$ This result has units of $kg$

$m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m$ This result has units of $kg$

$\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C$ This result has units of $kg \frac{m^{3}}{s^{3}}$ and $C$ is a constant