We got the following:
m = 78kg
h = 6m
g = 9.8 m/
≈ 10 m/
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A = ?
As we know A = Ep = mgh -> potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule
Answer:
Explanation:
Given that
Mass of rifle = M
Initial velocity ,u= 0
Mass of bullet = m
velocity of bullet = v
Lets take final speed of the rifle is V
There is no any external force ,that is why linear momentum of the system will be conserve.
Initial linear momentum = Final linear momentum
M x 0 + m x 0 = M x V + m v
0 = M x V + m v
Negative sign indicates that ,the recoil velocity will be opposite to the direction of bullet velocity.
Answer:
T = 686.7N
Explanation:
For this exercise we will use Newton's second law in this case there is no acceleration,
∑ F = ma
T -W = 0
The gymnast's weight is
W = mg
We clear and calculate the tension
T = mg
T = 70 9.81
T = 686.7N
As we know that Nth harmonic of the string is given by
now here we will have
now from above formula we have
now for first harmonic N = 1
for second harmonic N = 2
for third harmonic N = 3
False the electro magnet is controlled electrically so its like turning on/off a switch thing of the magnets they have at junkyards.
