use the formula
v= u+ at
v is final velocity , u is initial velocity , a is acceleration and t is time
put the values
20 = 0+ a×5
a = 4 m/s²
Answer:
The work done by this force can be found via the following formula

Explanation:
Alternatively, the work done by the object is equal to the elastic potantial energy done by the spring.

Answer:
2 * 10^5 pa
Explanation:
Pressure = Force / Area
Each thigh bone has a cross sectional area of 10cm²
Both thigh bones :
2 * 10cm² = 20cm²
To m² : 20 * (0.01)²
20 * 0.0001 m² = 0.002 m²
Force = mass * acceleration due to gravity(g)
g = 10m/s² ;
Force = 40 * 10 = 400N
Pressure = 400 N / 0.002 m²
Pressure = 200,000 N/m² = 2 * 10^5 pascal
Answer:
The answer to your question is : 521.8 m
Explanation:
Data:
Different heights
Time first object (tfo) = 10.7 s
Time second object (tso)= 14.8 s
Initial speed of both objects(vo) = 0 m/s
a = 9.81 m/s²
Formula:
h = vot + 1/2 (a)(t)² but vo = 0 so, h = 1/2 (a)(t)²
Then, height fo h = 1/2 (9.81)(10.7)² = 561.6 m
height so h = 1/2(9,81)(14.8)² = 1074.4 m
Difference in their heights = 1074.4 m - 561.6 m = 521.8 m