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Stella [2.4K]
3 years ago
9

From a lake, water is pumped at a rate of 67 L/s to a storage tank positioned 14 m above while consuming 16.4 kW of electrical p

ower. (Assuming no frictional losses or kinetic energy change taking place), determine the overall efficiency of the pump-motor unit. (Take gravitational acceleration as 10 m/s2).
Physics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

57 %

Explanation:

input power = 16.4 kW = 16.4 x 10^3 W = 16400 W

Water pumped per second = 67 L/s

Mass of water pumped per second, m = Volume of water pumped epr second x density of water

m = 67 x 10^-3 x 1000 = 67 kg/s

height raised, h = 14 m

Output Power = m x g x h / t = 67 x 10 x 14 = 9380 W

efficiency = output power / input power = 9380 / 16400 = 0.57

% efficiency = 57 %

thus, the efficiency of the pump is 57 %.

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Consider a coccus and a rod of equal volume. Which is more likely to survive in a dry environment? Explain your answer Which wou
Oxana [17]

Answer:

Coccus  is suitable for dry environment and a rod is better adapted for moist environment.

Explanation:

The probability of Coccus would be  better suitable for a environment which is dry. A sphere posses less surface area for the volume, as such,  moisture which is  lost through osmosis  is less in dry environment conditions.

During a moist environment, the ratio of the surface area to volume of a rod shaped bacterium is high, which allow higher efficiency to transfer water and solutes into and outside of the cell, and to make possible for a cell which is in rod shaped, have a metabolic rate higher.

4 0
4 years ago
An airplane accelerates from rest down a runway at 3.20 m/s2 for 32.8 seconds until it lifts off the ground. Determine the dista
vagabundo [1.1K]

Answer:

s=1721.344m  ,v=104.96m/s.

Explanation:

using thr equation of motion;

s=ut+\frac{1}{2}at^{2}

u=0, plane starts from rest,

s=\frac{1}{2}at^{2}

a=3.2m/s^{2}, t=32.8s \\ s=\frac{1}{2}*3.2*32.8^{2}

s=1721.344m

v=u+at

v=0 +3.2*32.8

v=104.96m/s

8 0
3 years ago
70 POINTS and BRAINLIEST! <br>Which segment represents freezing? <br>E-D <br>D-C<br>C-B <br>B-A​
cluponka [151]

Answer:

the answer is c) C-B

Explanation:

i just took the test

5 0
3 years ago
What is the strength of the electric field in a region where the electric potential is constant?
Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx        ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

4 0
3 years ago
The mass of a golf ball is 45.9 g . if it leaves the tee with a speed of 62.0 m/s , what is its corresponding wavelength?
inn [45]

The wavelength of the golf ball is <u>2.328×10⁻³⁴m.</u>

All moving particles with mass have a matter wave associated with it. These matter waves are called deBroglie waves.

The deBroglie wavelength λ of a particle is given by,

\lambda=\frac{h}{mv}

Here, h is the Planck's constant, m is the mass of the ball and v is its velocity.

Calculate the deBroglie wavelength of the moving golf ball by substituting 6.626×10⁻³⁴J s for h, 45.9×10⁻³kg for m and 62.0 m/s for v.

\lambda=\frac{h}{mv}\\ =\frac{6.626*10^-^3^4Js}{(45.9*10^-^3kg)(62.0m/s)} \\ =2.328*10^-^3^4m

The wavelength of the golf ball is  <u>2.328×10⁻³⁴m.</u>




4 0
4 years ago
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