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Stella [2.4K]
3 years ago
9

From a lake, water is pumped at a rate of 67 L/s to a storage tank positioned 14 m above while consuming 16.4 kW of electrical p

ower. (Assuming no frictional losses or kinetic energy change taking place), determine the overall efficiency of the pump-motor unit. (Take gravitational acceleration as 10 m/s2).
Physics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

57 %

Explanation:

input power = 16.4 kW = 16.4 x 10^3 W = 16400 W

Water pumped per second = 67 L/s

Mass of water pumped per second, m = Volume of water pumped epr second x density of water

m = 67 x 10^-3 x 1000 = 67 kg/s

height raised, h = 14 m

Output Power = m x g x h / t = 67 x 10 x 14 = 9380 W

efficiency = output power / input power = 9380 / 16400 = 0.57

% efficiency = 57 %

thus, the efficiency of the pump is 57 %.

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Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

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v = Final velocity = 0 km/h

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a = Acceleration

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g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

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8 0
3 years ago
I need help with this
Fed [463]
HEY THERE !!

It is called SUBLIMATION.

so the correct answer is (D).
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Therefore, there are 5.1 x10^22 electrons that assed through the heater for 10 minutes.
3 0
3 years ago
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