Answer:
Please find the answer in the explanation
Explanation:
1.) How far is Object Z from the origin at t = 3 seconds
The distance of the object Z from the origin will be the slope of the graph.
Slope = 4/2 = 2m
2.) Which object takes the least time to reach a position 4 meters from the origin ?
According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.
3.) Which object is farthest from the origin at t = 2 seconds?
The correct answer is still object Z because it has the highest slope.
Because an object in rest stays in rest until an unequal force pushes it so gravity is pushing on the egg making it drop
Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V
Explanation: In order to solve this problem we have to consider the energy balance for the photoelectric effect on tungsten:
h*ν = Ek+W ; where h is the Planck constant, ek the kinetic energy of electrons and W the work funcion of the metal catode.
In order to calculate the cutoff wavelength we have to consider that Ek=0
in this case h*ν=W
(h*c)/λ=4.52 eV
λ= (h*c)/4.52 eV
λ= (1240 eV*nm)/(4.52 eV)=274.34 nm
From this h*ν = Ek+W; we can calculate the kinetic energy for a radiation wavelength of 198 nm
then we have
(h*c)/(λ)-W= Ek
Ek=(1240 eV*nm)/(198 nm)-4.52 eV=1.74 eV
Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this acts to slow down the ejected electrons from the catode.