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natulia [17]
3 years ago
5

PLEASE PLEASE HELP

Physics
1 answer:
pav-90 [236]3 years ago
6 0

if in series one lightbulb burns out the rest are unable to turn on.

In parallel a single light bulb burns out any other light bulbs are able to work.

Parallel is the best to use during holidays.

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What is the primary difference between an ideal emf device and a real emf device?.
EleoNora [17]

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A real emf device has an internal resistance, but an ideal emf device does not.

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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T on Earth. Calculate the
melamori03 [73]

Answer:

T = T

Explanation:

Time period of a simple pendulum is not affected by the mass of the bob. As we know, T = 2\pi \sqrt{L/g} . There is no factor of mass affecting when we derived the equation. The basic reason behind the time period is not affected is because of mass dependence on angular acceleration. As the mass increases the acceleration increase and the Time Period remains constant.

8 0
3 years ago
4. What is the instantaneous acceleration at t= 10 s?
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I am fairly certain the answer is 2m/s^2

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6 0
3 years ago
With what minimum speed must you toss a 200 g ball straight up to just touch the 12-m-high roof of the gymnasium if you release
masha68 [24]

Answer:

v = 14.41 m/s

Explanation:

It is given that,

mass of the ball, m = 200 g = 0.2 kg

Height of the roof, h = 12 m

The ball is tossed 1.4 m above the ground, h' = 1.4 m

Let v is the minimum speed with which the ball is tossed. Using the conservation of energy to find it as :

E_p=E_k

mg(h-h')=\dfrac{1}{2}mv^2

g(h-h')=\dfrac{1}{2}v^2

v=\sqrt{2g(h-h')}

v=\sqrt{2\times 9.8(12-1.4)}

v = 14.41 m/s

So, the minimum speed with which the ball is thrown straight up is 14.41 m/s. Hence, this is the required solution.

4 0
3 years ago
stephanie, who has a mass of 75 kg is driving and suddenly slams on her brakes to avoid hitting a student crossing blanco road.
11111nata11111 [884]

Answer:

25 m/s

Explanation:

Impulse = change in momentum

F Δt = m Δv

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v = 25 m/s

5 0
3 years ago
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