Changes. :) I think... Whats your question
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Answer:
The velocity of the camera is 33.11 m/s.
Explanation:
Given that,
Speed = 10.8 m/s
Altitude = 50 m
Suppose determine the velocity of the camera just before it hits the ground?
We need to calculate the velocity of the camera
Using equation of motion
Where, v = final velocity of camera
u = initial speed of camera
s = distance
Put the value into the formula
The direction will be downward so it is the negative velocity.
Hence, The velocity of the camera is 33.11 m/s.
Answer:
The ball will be attracted to the negatively charged plate. It'll touch and pick up some electrons from the plate so that the ball becomes negatively charged. Immediately the ball is repelled by the negative plate and is attracted to the positive plate. The ball gives up electrons to the positive plate so that it is positively charged and suddenly attracts to the negative plate again, flies over to it and picks up enough electrons to be repulsed by negative plate and again to the positive plate and that continues.
Answer:
Less
Explanation:
Since acceleration is inversely propotional to mass keeping the force constant, hence more mass will accelerate less and vice versa.
