Answer:
Option A. 25.7 L.
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial volume (V1) = 37.2 L
Initial pressure (P1) = 362.43 kPa
Initial temperature (T1) = 46.5 °C
Final pressure (P2) = 693.9 kPa
Final temperature (T2) = 149.2 °C
Final volume (V2) =.?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This can be achieved as shown below:
Temperature (K) = Temperature (°C) + 273
T (K) = T (°C) + 273
Initial temperature (T1) = 46.5 °C
Initial temperature (T1) = 46.5 °C + 273 = 319.5 K.
Final temperature (T2) = 149.2 °C
Final temperature (T2) = 149.2 °C + 273 = 422.2 K.
Step 3:
Determination of the new volume.
This can be obtained by using the general gas equation as shown below:
Initial volume (V1) = 37.2 L
Initial pressure (P1) = 362.43 kPa
Initial temperature (T1) = 319.5 K
Final pressure (P2) = 693.9 kPa
Final temperature (T2) = 422.2 K
Final volume (V2) =.?
P1V1/T1 = P2V2/T2
362.43×37.2/319.5 = 693.9 × V2/422.2
Cross multiply
319.5×693.9×V2 = 362.43×37.2×422.2
Divide both side by 319.5 × 693.9
V2 = (362.43×37.2×422.2)/(319.5×693.9)
V2 = 25.7 L
Therefore, the new volume is 25.7 L.
